Which of the following has maximum number of atoms?
(a) 18 g of H2O
(b) 18 g of O2
(c) 18 g of CO2
(d) 18 g of CO4​

Answers

Answer 1

Answer:

(a) 18 g of H2O

Explanation:

The molecule with great number of moles will have great number of atoms.

By observation, since all compounds have same mass, water has the least molcular mass

[tex]H_{2} O = \: 18 \: g[/tex]

Answer 2

Answer:

18g of H2O

Explanation:

the molecule with great number of moles will have great number of atoms .

(a) option is correct


Related Questions

WILL MARK BRAINLY IF GOOD ANSWER :)
Chlorine and oxygen are both gases at room temperature. What are some characteristic properties of chlorine that distinguish it from oxygen?

Answers

Answer:

Well one characteristic is electical energy transforms into  thermal energy and gases and the state of matter(one of the distinct form i which  matter exist)

How much heat is added if .0948g of water is increased in temperature by .728 degrees C?


.289 J

.803 J

1.46 J

.055 J

Answers

Answer:

0.289J of heat are added

Explanation:

We can relate the change in heat of a substance with its increasing in temperature using the equation:

q = m*ΔT*S

Where Q is change in heat

m is mass of substance (In this case, 0.0948g of water)

ΔT = 0.728°C

S is specific heat (For water, 4.184J/g°C)

Replacing:

q = 0.0948g*0.728°C*4.184J/g°C

q = 0.289J of heat are added

calculate the maximum mass of ethanol that could be obtained from 30.0g of glucose​

Answers

Answer:

15.3g

Explanation:

C6H12O6 → 2C2H5OH + 2CO2

1 mol C6H12O6 = 180g

1 mol CH3-CH2-OH = 46g

From 180g glucose ethanol can get = 92g

30g glucose ethanol gives us = (92*30)/180 = 15.33g

Balance in basic solution: O2(g) + Cr³+ (aq) → H₂O2 (1) + Cr₂O7²- (aq)

Answers

cr2o72+H2o2-(r3+o2)

Explanation:

r62o72+H2o2-(r3+o2)

what is the balanced equation of 2HCl + Mg - MgCla + Ha​

Answers

2HCl + Mg => MgCl2 + H2

solution is an example of______mixtures​

Answers

Answer:

homogeneous mixture must be the answer

Doing my summer school work right now. Please help me pass I don’t want to take chemistry for the third time.

Answers

Answer:

13.B 0.15 M KBr

14.C 1 M C²h⁵OH

15.D 0.1 M C⁶H¹²o⁶

16.A 2 K² SO⁴

17.A 2 M K² SO⁴

18.D 0.028 M KBr

19.A 1 M Nal

20.B 0.1 M AICI³

Define physical and chemical properties, provide three examples of each, discuss their reversibility, and explain the fundamental differences between them.

Answers

Answer:

Physical properties are defined as the properties which can be observed without changing their chemical composition.

For example, color, volume, and molecular weight.

Chemical properties can be defined as, a properties that can be seen only after changing the substance's chemical identity.

For example, reactivity, toxicity, and flammability.

The fundamental differences between physical and chemical properties are as follows:

Chemical properties are related to chemical bonds of the substance, while physical properties are not.

In chemical properties, the chemical identity of substance changes while physical properties does not have any change.

Chemical properties predict the reaction of a substance, while physical properties only describe the appearance of the substance.

   

Explanation:

1125 J of energy is used to heat 250 g of iron to 55 °C. The specific heat capacity of iron is 0.45 J/(g·°C).

What was the temperature of the iron before it was heated?

55 °C
55 °C

35 °C
35 °C

45 °C
45 °C

20 °C

Answers

Answer:

45 °C.

Explanation:

From the question given above, the following data were obtained:

Heat (Q) = 1125 J

Mass (M) = 250 g

Final temperature (T₂) = 55 °C

Specific heat capacity (C) = 0.45 J/gºC

Initial temperature (T₁) =?

The initial temperature of the iron can be obtained as illustrated below:

Q = MC(T₂ – T₁)

1125 = 250 × 0.45 (55 – T₁)

1125 = 112.5 (55 – T₁)

Divide both side by 112.5

1125/112.5 = 55 – T₁

10 = 55 – T₁

Collect like terms

10 – 55 = –T₁

–45 = –T₁

Multiply through by –1

45 = T₁

T₁ = 45 °C

Therefore, the initial temperature of the iron is 45 °C

Which of the following is the formula for vanadium (II) oxide? Question 11 options: A) VO2 B) VO C) V2O3 D) V2O5

Answers

Answer: A. ( VO2)

Explanation:

Answer:

B) VO

Vanadium(II) oxide is the inorganic compound with the idealized formula VO.

PLZ HELP ME Which of the following is the process by which chloroplasts use carbon dioxide, water, and sunlight to produce sugars and oxygen?
A. Photosynthesis
B. Cellular respiration
c. Reproduction
D. Homeostasis​

Answers

Answer:

a

Explanation:

The answer is Photosynthesis

what is the most appropriate unit to measure the following; the length of a football field. b) the diameter of a tennis ball​

Answers

Explanation:

a) m (metre)

b) mm (millimeter)

Formation of HCl from H₂and Cl₂ is example of

photochemical

electrochemical

displacement​

Answers

Answer:

Combination reaction.

Explanation:

The reaction depicted in the question is;

H2 (g) + Cl2 (g) ⟶ 2HCl (l)

Now, this reaction shows that two reactants namely hydrogen and chlorine react to form a single product named Hydrogen chloride. This process is called combination reaction.

HF or HCl which can form the hydrogen bond? Explain your answer.​

Answers

Answer:

can only form one hydrogen bond each

Explanation:

can only form one hydrogen bond each

Which reaction occurs at the cathode in an electrochemical cell?
A. Cu(s) → Cu2+(aq) + 2e
B. Cu2+(aq) + H2(g) → Cu(s) + 2H+(aq)
C. Cu(s) + 2H+(aq) → Cu2+(aq) + H2(g)
D. Cu2+(aq) + 2e → Cu(s)

Answers

Answer:

I could be wrong but I say it's letter b

Explanation:

I hope you have an great night

calculate the number of atoms in 1g of calciumj​

Answers

Answer:

It's about mass of 40.1⋅g

Explanation:

I hope this helps you out. Have a nice day!

The volume of a gas was 48 mL when the temperature was 159.6 ºC. If the temperature was initially 4.9 ºC, and there was no change in the pressure, what was the initial volume of the gas?

Answers

V1=48mLT1=159.6°CT2=4.9°CV2=?

According to Charles law

[tex]\boxed{\sf \dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}}[/tex]

[tex]\\ \sf\longmapsto \dfrac{48}{159.6}=\dfrac{V_2}{4.9}[/tex]

[tex]\\ \sf\longmapsto V_2=\dfrac{48\times 4.9}{159.6}[/tex]

[tex]\\ \sf\longmapsto V_2=\dfrac{235.2}{159.6}[/tex]

[tex]\\ \sf\longmapsto V_2=1.4mL[/tex]

Which of the following materials contains a base?

a. Stomach digestive juices
b. Orange juice
c. Ammonia window cleaner
d. Vinegar

Answers

Answer:

c. ammonia window cleaner

Explanation:

Window cleaners contain ammonia (a base) for the purpose of removing the dust and grease on the windows.

digestive juices, orange(a citrus) juice, and vinegar are all highly acidic.

... give me brainliest please :)) ...

Infrared waves are an example of heat transfer by
A. convection
B. radiation
C. conduction
D. motion of the air

Answers

Answer:

convection is my correct answer

Identify any three acids.
Identify any three bases.

Answers

Acids:
Sulfuric acid, hydrochloric acid, nitric acid,

Bases:
Potassium hydroxide (KOH)
Sodium hydroxide (NaOH)
Barium hydroxide (Ba(OH)2)

What is the pressure of 4 moles of helium in a 50 L tank at 308 K?
Use PV = nRT.
A. 24.64 atm
B. 0.13 atm
O C. 0.51 atm
D. 2.02 atm

Answers

Answer:

D

Explanation:

P = Pressure

V = Volume

n = Moles

R = .08206 (because we're using liters)

T = Temperature (as K)

P(50) = (4)(.08206)(308)

P(50) = 101.09792

Divide both sides by 50

P(50)/50 = 101.09792/50

P = 2.0219584

Answer:

[tex]\boxed {\boxed {\sf D. \ 2.02 \ atm}}[/tex]

Explanation:

We are asked to find the pressure of helium gas using the ideal gas law.

[tex]PV= nRT[/tex]

In this formula P is the pressure, V is the volume, n is the number of moles of gas, R is the universal gas constant, and T is the temperature.

The pressure is unknown and we are solving for it. The volume is 50 liters, there are 4 moles of helium gas, the universal gas constant is 0.08206 L *atm/ mol * K, and the temperature is 308 Kelvin.

[tex]\bullet \ V= 50 \ L \\\bullet \ n= 4 \ mol \\\bullet \ R = \frac {0.08206 \ L * atm}{mol *K}\\\bullet \ T= 308 \ K[/tex]

Substitute these values into the formula.

[tex]P * 50 \ L= 4 \ mol * \frac {0.08206 \ L * atm}{mol *K} * 308 \ K[/tex]

Multiply on the right side. The units of moles (mol)  and Kelvin (K) cancel each other out.

[tex]P* 50 \ L = 4 * 0.08206 \ L *atm * 308[/tex]

[tex]P*50 \ L =0.32824 \ L * atm *308[/tex]

[tex]P* 50 \ L = 101.09792 \ L * atm[/tex]

We are solving for the pressure, so we must isolate the variable P. It is being multiplied by 50 liters. The inverse operation of multiplication is division, so divide both sides by 50 L.

[tex]\frac {P* 50 \ L}{50 \ L} = \frac {101.09792 \ L * atm}{50 \ L}[/tex]

[tex]P= \frac {101.09792 \ L * atm}{50 \ L}[/tex]

The units of liters (L) cancel.

[tex]P= \frac{101.09792}{50 } \ atm[/tex]

[tex]P= 2.0219584 \ atm[/tex]

If we round to the nearest hundredth place the 1 in the thousandth place tells us to leave the 2 in the hundredth place.

[tex]P \approx 2.02 \ atm[/tex]

The pressure is approximately 2.02 atmospheres and choice D is correct.

Oxit bazơ có những tính chất hóa học nào?

Answers

Answer:

tác dụng với acid,

Explanation:

calcium hydrogen sulphite cress cross

Answers

Answer:

Ca Hso4 ×

Explanation:

Because i did whT you said

Which factors ALL increase reaction rate?


decrease temperature, stir, increase surface area, remove catalyst

none of these

increase temperature, increase surface area, add catalyst, stir

increase temperature, stir, decrease surface area, add catalyst

Answers

Answer:

increase temperature, increase surface areas, add catalyst, stir

The rate of reaction can be increased with the increase in temperature, surface area, adding catalyst and allowing stirring. Thus, option C is correct.

What is rate of reaction?

The rate of reaction is given as the rate of formation of product or the rate of disappearance of reactant in unit time.

The rate of reaction can be affected with:

Increase in temperature - It will increase the collisions between the reactants, and thereby the rate.

Increase in surface area - It results in increased interaction of the reactant molecules for the formation of product.

Catalyst - It lowers the activation energy of the reactant, and thereby increases the rate of reaction.

Stirring - It mediates the increase in the collisions and the surface area, and resulting in increased rate of reaction.

Thus, the rate of reaction can be increased with the increase in temperature, surface area, adding catalyst and allowing stirring. Thus, option C is correct.

Learn more about rate of reaction, here:

https://brainly.com/question/13440548

#SPJ2

2 Figure 3.1 shows two different forms of carbon, A and B.
A
B
Figure 3.1
a Name the two forms of carbon shown.

Answers

Answer:

show the pictures pls specify

aluminum hydroxide molecular weight step by ste​

Answers

Hydroxide step by ste

The unit of force newton is a derived unit.Why?

Answers

Answer:

Why is the unit of force called a derived unit? That's because the Newton is defined in terms of other units which are more fundamental. One Newton is the force required to accelerate a mass of one kilogramme at the rate of one metre per second squared.

Which of the following is an example of a chemical change?
A. Sugar breaking down into water and carbon when it is heated
B. A sugar cube being crushed by a spoon
C. Sugar mixing with red food coloring and forming a red solid
D. A sugar cube dissolving in water as the water is stirred

Answers

Answer:

I think its sugar breaking down into watee and carbon when it is heated

I HOPE ITS RIGHT IF NOT THEN SORRY

HAVE A GREAT DAY :)

Question 2: thanks!!!

Answers

Ans 33333333333333333333333333 cellulose

A fixed mass of gas has a volume of 92 cm cube and 3 degrees Celsius. What will be its volume at 18 degrees celsius if the pressure remains constant?​

Answers

Answer:

94.8454

Explanation:

Let volume be V

Let Temperature be T

V1= 92

T1= 3C but to kelvin 273+3= 300K

V2= ?

T2= 18 C but to kelvin 18+273= 291

[tex] \frac{v1}{t1} = \frac{v2}{t2} [/tex]

[tex] \frac{92}{300} = \frac{v2}{291} [/tex]

[tex]v2 \times 300 = 92 \times 291[/tex]

[tex]v2 = \frac{92 \times 291}{300} [/tex]

[tex]v2 = 94.8454[/tex]

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