Which pair of angles are corresponding angles?

Answer:

1.92 m³

hopefully this answer can help you to answer the next question.

Answer:

Perimeter of XYZ = Perimeter of QRP

Step-by-step explanation:

Since congruent then

P of XYZ = P of QRP

Answer:

x = 139

Step-by-step explanation:

The exterior angle is equal to the sum of the opposite interior angle

x = 49 +90

x = 139

An exterior angle of a triangle is equal to the sum of its interior opposite angles.

[tex] \bf \large \implies \: x \: = \: 49 \degree \: + \: 90 \degree[/tex]

[tex] \bf \large \implies \: x \: = \: 139 \degree [/tex]

Answer:

A=2

B=4

C=6

D=5

E=7

F=8

G=3

H=1

Step-by-step explanation:

explanation is in the picture!

Answer:

[tex]x + y = - 5[/tex]

Step-by-step explanation:

hopefully it is clear and makes sense

:)

The question is incomplete. The complete question is :

In a survey of women in a certain country ( ages 20-29), the mean height was 62.9 inches with a standard deviation of 2.81 inches.  Answer the following questions about the specified normal distribution.  (a) What height represents the 99th percentile?  (b) What height represents the first quartile?  (Round to two decimal places as needed)

Solution :

Let the random variable X represents the height of women in a country.

Given :

X is normal with mean, μ = [tex]62.9[/tex] inches and the standard deviation, σ = [tex]2.81[/tex] inches

Let,

[tex]$Z=\frac{X - 62.9}{2.81}$[/tex] , then Z is a standard normal

a). Let the [tex]99th[/tex] percentile is = a

The point a is such that,

[tex]$P(X<a)=0.99$[/tex]

[tex]$P \left( Z < \frac{a-62.9}{2.81} \right) = 0.99$[/tex]

From standard table, we get : [tex]P( Z < 2.3263) =0.99[/tex]

∴ [tex]$\frac{(a-62.9)}{281} = 2.3263$[/tex]

  [tex]$a= (2.3263 \times 2.81 ) +62.9$[/tex]

     = 6.536903 + 62.9

     = 69.436903

     = 69.5 (rounding off)

Therefore, the height represents the [tex]99th[/tex] percentile = 69.5 inches.

b). Let b = height represents the first quartile.

It is given by :

[tex]P( X < b) =0.25[/tex]

[tex]$P \left( Z < \frac{(b-62.9)}{2.81} \right) = 0.25$[/tex]

From the standard normal table,

[tex]P( Z < -0.6745) =0.99[/tex]

∴ [tex]$\frac{(b-62.9)}{2.81}= 0.6745$[/tex]

[tex]$b=(0.6745 \times 2.81) +62.9$[/tex]

  = 1.895345 + 62.9

   = 64.795345

   = 64.8 (rounding off)

Therefore, the height represents the 1st quartile is 64.8 inches.

Answer:

area = 8 × 18 = 144 cm^2

volume 8×18×5 = 720cm^3

Answer:

12

Step-by-step explanation:

4s multiples:

4,8,12,16,20,24

6s multiples:

6,12,18,24,30,36

lowest number that is a common multiple between both 4 and 6:

12

Answer: 2

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

area=1/2×32×6.1=16×6.1=97.6 yd²

Answer:

Choice B. 97.6 yd^2

Step-by-step explanation:

B×W×.5= A

Answer:

4/5 or 0.8

Step-by-step explanation:

this problem description is not very precise. it leaves out the definition what corners or sides of JKLM correspond to corners and sides of ABCD.

I assume J and K correlate to A and B, and JK is a long side of JKLM.

so, we are going from JKLM to ABCD.

that means we are going from larger to smaller (as JK = 15 and therefore larger than AB = 12).

what is the scale factor to go from 15 to 12 ?

15 × x = 12

x = 12/15 = 4/5 or 0.8

The equation has two real and equal roots for [tex]k = \frac{5}{6}[/tex]

In this question, we use the concept of the solution of a quadratic equation to solve it, considering that a quadratic equation in the format:

[tex]ax^2 + bx + c = 0[/tex]

has two equal solutions if [tex]\Delta = b^2 - 4ac[/tex] is 0.

------------------------------------

In this question:

The equation is:

[tex](2k+1)x^2 + 2x = 10x - 6[/tex]

Placing in the correct format:

[tex](2k+1)x^2 + 2x - 10x + 6 = 0[/tex]

[tex](2k+1)x^2 - 8x + 6 = 0[/tex]

Thus, the coefficients are: [tex]a = 2k + 1, b = -8, c = 6[/tex]

------------------------------------

Delta:

We want it to be positive, so:

[tex]\Delta = b^2 - 4ac[/tex]

[tex]\Delta = 0[/tex]

[tex]b^2 - 4ac = 0[/tex]

[tex](-8)^2 - 4(2k+1)(6) = 0[/tex]

[tex]64 - 48k - 24 = 0[/tex]

[tex]-48k + 40 = 0[/tex]

[tex]-48k = -40[/tex]

[tex]48k = 40[/tex]

[tex]k = \frac{40}{48}[/tex]

[tex]k = \frac{5}{6}[/tex]

The equation has two real and equal roots for [tex]k = \frac{5}{6}[/tex]

A similar question is found at https://brainly.com/question/12144265

Answer: (b)

Step-by-step explanation:

Given

There are five consecutive integers and the least minus twice the greatest equals to -3

Suppose [tex]x,x+1,x+2,x+3,x+4[/tex] are the five consecutive integers

According to the question

[tex]\Rightarrow x-2(x+4)=-3\\\Rightarrow x-2x-8=-3\\\Rightarrow -x=8-3\\\Rightarrow x=-5[/tex]

option (b) is correct.

Answer:

[tex]\displaystyle d \approx 15.8768[/tex]

Step-by-step explanation:

We want to find the distance of d or AB.

From the right triangle with a 35° angle, we know that:

[tex]\displaystyle \tan 35^\circ = \frac{50}{PB}[/tex]

And from the right triangle with a 42° angle, we know that:

[tex]\displaystyle \tan 42^\circ = \frac{50}{PA}[/tex]

AB is PA subtracted from PB. Thus:

[tex]\displaystyle d = AB = PB - PA[/tex]

From the first two equations, solve for PB and PA:

[tex]\displaystyle \frac{1}{\tan 35^\circ } = \frac{PB}{50} \Rightarrow PB = \frac{50}{\tan 35^\circ}[/tex]

And:

[tex]\displaystyle \frac{1}{\tan 42^\circ } = \frac{PA}{50} \Rightarrow PA = \frac{50}{\tan 42^\circ}[/tex]

Therefore:

[tex]\displaystyle d = AB = \frac{50}{\tan 35^\circ} - \frac{50}{\tan 42^\circ}[/tex]

Using a calculator:

[tex]\displaystyle d= AB \approx 15.8768[/tex]

Answer:

B

Step-by-step explanation:

The decimal number 0.00897 written in scientific notation is 8.97 ×10^3 and it has significant figures

Answer:

8.97 * 10⁻³

Step-by-step explanation:

0.00897 = [tex]\frac{8.97}{1000}=8.97 * 10^{-3}[/tex]

Place the decimal point after the first nonzero number.

Write the power of 10,

(i) If we move the decimal to the right, the power of 10 decrease by number of moves.

(ii) If we move the decimal to the left, the power of 10 increase by the number of moves

Image of figure ABCD is missing and so i have attached it.

Answer:

D_new = (-1, - 12)

Step-by-step explanation:

From the figure attached, the current coordinates of D are; (-5, -2)

Now, we are told the figure undergoes a translation of (x,y) (x+6,y-10)

Thus, this means we add 6 to the x value and subtract 10 from the y-value.

Thus, new coordinate of D is;

> (-5 + 6, -2 - 10)

> (-1, - 12)

Answer:

1, -12

Step-by-step explanation:

D = -5, -2

|

-5 + 6 = 1

|

-10 and -2 is -12

1, -12

did it on edge, got it right.

Answer:

I am so lost but if it's how many honk out of how many you saw I would assume 7/7

Answer:

C

Step-by-step explanation:

Polygon 3 and 5 are congruent cause they have the same length of side

Answer:

MZ = 10

ZO = 10

MO = 20

XZ = 9

YZ = 7

Step-by-step explanation:

Triangles are all the same, proportionally.

X is midpoint of 14, so 7

Y for 18, so 9

Triangle with 10 is 7, 9, 10

Full triangle is double at 14, 18, MO

Since angle N is same angle, MO is double 10, so 20

Z is midpoint, so both halves are 10

Because of midpoints, XZ and YZ with 10 form same triangle as half triangle at 9, 7, and 10 respectively.

Answer:

Front = 30

Back = 30

Right = 30

Left = 30

Bottom = 25

Top = 16

Total = 161

Let me know if this helps!

The quadratic equation that could be solved using the given application of the quadratic formula is x² + 2x - 1 = 3, which in standard form is x² + 2x - 4 = 0. Hence, option C is the right choice.

A standard quadratic equation of the form ax² + bx + c = 0, can be solved using the quadratic formula, which is given as:

[tex]x = \frac{-b\pm\sqrt{b^2-4ac} }{2a}[/tex]

In the question, we are asked for the quadratic equation, which could be solved using this application of the quadratic formula:

[tex]x = \frac{-2\pm\sqrt{2^2-4(1)(-4)} }{2(1)}[/tex]

To find the quadratic equation for which we use the quadratic formula

[tex]x = \frac{-2\pm\sqrt{2^2-4(1)(-4)} }{2(1)}[/tex]

we compare this equation with the standard quadratic formula,

[tex]x = \frac{-b\pm\sqrt{b^2-4ac} }{2a}[/tex]

to get a = 1, b = 2, and c = -4, to get the standard quadratic equation, ax² + bx + c = 0, as (1)x² + (2)x + (-4) = 0, or x² + 2x - 4 = 0.

Now, we convert the given options in the standard form to check for the correct choice:

Thus, the quadratic equation that could be solved using the given application of the quadratic formula is x² + 2x - 1 = 3, which in standard form is x² + 2x - 4 = 0. Hence, option C is the right choice.

Learn more about the quadratic formula at

https://brainly.com/question/1214333

#SPJ2

Hi there!

[tex]\large\boxed{(2, 8)}[/tex]

Solve by setting the two equations equal to each other:

-2x² + 4x + 8 = -4x + 16

Move all terms to one side:

-2x² + 4x + 4x + 8 - 16 = 0

Simplify:

-2x² + 8x - 8 = 0

Factor out a negative 2 from each term:

-2(x² - 4x + 4) = 0

Factor:

-2(x - 2)² = 0

Set the factor equal to 0 to solve:

(x - 2)² = 0

x - 2 = 0

x = 2

Substitute this value of x into an equation to find the shared y value:

y = -4(2) + 16 = 8

does it give the answer choice or is it a blank space?

Answer:

-25

Step-by-step explanation:

First, add 5 to -23 since the temperature is getting hotter.

so -23 +5= -18

Second, minus the answer by 7 since the temperature is now falling down after the sunset.

so -18 -7 = -25

or...

this step can be simplified as:

-23 +5 -7 =. -25

Answer:

Step-by-step explanation:

The missing length is 13 because,

Lets say the top triangle is A and the bottom triangle is B.

Triangle A gives us the side GF, and Triangle B gives us the sides TU and ST. Since the triangles are similar(as stated in the problem), we can pair 2 sides GF(A) and TU(B) which is 11:22.(one way I usually figure which sides are similar is by first- matching the hypotenuse, then checking which of the remaining two is longer.. if that made any sense). You can see that their relationship is x2 or /2 (In another word, from A to B is multiplication- ex: 11 * 2 is 22, and from B to A is division- ex 22/2 is 11.) Since the missing number is the hypotenuse of triangle A and you know the Hypotenuse of triangle B all you have to do is divide side TS by 2 to get side SF. So the missing side is 13.

Answer: 13

Answer:

1) The total displacement vector is ((16 + √2)/2, -(6+11·√2)/2)

2) The number of miles they'd have to walk is approximately 13.856 miles

Step-by-step explanation:

1) The distance, direction, and location of the path of the walk the person takes,  are listed as follows;

Start location, (0, 0)

6 miles East walk to location, (6, 0)

6 miles Southeast to location, (6 + 3·√2, -3·√2)

3 miles South to location, (6 + 3·√2, -3·√2 - 3)

5 miles Southwest to location, (6 + 3·√2 - 2.5·√2, -3·√2 - 3 - 2.5·√2)

2 miles East to location, (6 + 3·√2 - 2.5·√2 + 2, -3·√2 - 3 - 2.5·√2)

(6 + 3·√2 - 2.5·√2 + 2, -3·√2 - 3 - 2.5·√2) = ((16 + √2)/2, -(6+11·√2)/2)

Therefore the destination coordinates is ((16 + √2)/2, -(6+11·√2)/2)

The total displacement vector, [tex]\underset{d}{\rightarrow}[/tex] = ((16 + √2)/2, -(6+11·√2)/2)

d =  (16 + √2)/2)·i - (6+11·√2)/2)·j

2) If the person walked straight home, the number of miles they'd have to walk, [tex]\left | \underset{d}{\rightarrow} \right |[/tex], is given as follows;

[tex]\left | \underset{d}{\rightarrow} \right | = \sqrt{\left(\dfrac{16 +\sqrt{2} }{2} \right)^2 + \left(-\dfrac{6 + 11 \cdot \sqrt{2} }{2} \right)^2 } = \sqrt{134 + 41 \cdot \sqrt{2} }[/tex]

Therefore;

If the person walked straight home, the number of miles they'd have to walk [tex]\left | \underset{d}{\rightarrow} \right | \approx 13.856 \ miles[/tex]