Y= 3x+6; (4,7) in slop intercept form

Answer:

Step-by-step explanation:

If these were similar, then the ratio 35/18 (the top and bottom measures from each of the polygons) would have to equal the ratio 63/10 (the side measures from each of the polygons).

35/18 = 1.944444

63/10 = 6.3

They are not similar because the simplified ratios are not the same.

Answer:

she's I'll ccgmf

Step-by-step explanation:

for the next day and night and it was so yitd cash check out j vfkcnc gjjx xh

Answer:

how much protein did he take per day tho?

Answer:

10/1

Step-by-step explanation:

5/6÷1/12

5/6×12/1 (do a inverse of 1 upon 12)

10/1

cancel 12 by 6

Answer:

B 48

Step-by-step explanation:

Ac=2AE, because AE=r, Ac=d, d=2r

Ac=2*5=10

The angle ADC is right, because it leans on the diameter AC,

find the leg DC, use the Pythagorus theorem

DC= sqrt (Ac^2-AD^2)= sqrt(100-36)=sqrt64=8

S= 6*8=48

Answer:

Step-by-step explanation:

Relations are only functions if they do not share any x values at all! The 2 graphs there that do not have any of the same x values are graphs A and D. Notice that on graph B, there are several y values that share the x value of 2; on graph C, there are several y values that share the x value of 2.

Answer:

A and D only

Step-by-step explanation:

A function is a relation where each input has its own output ( each x values has its own corresponding y value ) If an input has more than one output than the relation is not a function.

We can tell if a graph shows a function or not by using the vertical line test. If you draw vertical lines on the graph and more than one point is on the vertical line drawn then the graph does not show a function.

For graph B if you draw a vertical line at x = -2 more than 1 point will be on the line meaning that the graph does not show a function.

For Graph C if you draw a vertical line at x = 2 more than 1 point will be on the line meaning that Graph C also does not show a function.

For Graphs A and D you can draw a vertical line anywhere on the graph and no more than 1 point will be on the line therefore Graphs A and D show functions.

Answer:

{2,4,5,6,8,10,15,20}

Answer:

{ 2,4,5,6,8,10,15,20}

Step-by-step explanation:

D ∪ E

This means the union of the two sets or what is in both circles with no duplicates

{ 2,4,5,6,8,10,15,20}

[tex]\\ \sf\longmapsto \left[{3a+b\atop a-b}\:\:\:{3c-d\atop a+b+d}\right]=\left[{3\atop 5}\:\:\;{6\atop 2d-1}\right][/tex]

Now constructing equations

[tex]\\ \sf\longmapsto 3a+b=3\dots(1)[/tex]

[tex]\\ \sf\longmapsto a-b=5\dots(2)[/tex]

[tex]\\ \sf\longmapsto 3c-d=6\dots(3)[/tex]

[tex]\\ \sf\longmapsto a+b+d=2d-1\dots(4)[/tex]

Adding eq(1) and (2)

[tex]\\ \sf\longmapsto 4a=8[/tex]

[tex]\\ \sf\longmapsto a=\dfrac{8}{4}[/tex]

[tex]\\ \bf\longmapsto a=2[/tex]

Put the value in eq(2)

[tex]\\ \sf\longmapsto a-b=5[/tex]

[tex]\\ \sf\longmapsto b=a-5[/tex]

[tex]\\ \sf\longmapsto b=2-5[/tex]

[tex]\\ \bf\longmapsto b=-3[/tex]

put the values in eq(4)

[tex]\\ \sf\longmapsto a+b+d=2d-1[/tex]

[tex]\\ \sf\longmapsto 2+(-3)+d=2d-1[/tex]

[tex]\\ \sf\longmapsto d-1=2d-1[/tex]

[tex]\\ \sf\longmapsto d-2d=-1+1[/tex]

[tex]\\ \sf\longmapsto -d=0[/tex]

[tex]\\ \bf\longmapsto d=0[/tex]

Put the value in eq(3)

[tex]\\ \sf\longmapsto 3c-d=6[/tex]

[tex]\\ \sf\longmapsto 3c-0=6[/tex]

[tex]\\ \sf\longmapsto 3c=6+0[/tex]

[tex]\\ \sf\longmapsto 3c=6[/tex]

[tex]\\ \sf\longmapsto c=\dfrac{6}{3}[/tex]

[tex]\\ \sf\longmapsto c=2[/tex]

Answer:

23 and 25

Step-by-step explanation:

Integers are whole numbers that are either positive, negative, or zero. Fractions and decimals are not integers. Therefore, 24 is between 23 and 25.

Answer:

Positive 23 and positive 25

Step-by-step explanation:

Answer:

I have to agree

it's A.

but I'm also thinking it's D.

Answer:

4.4

Step-by-step explanation:

Answer:

t = 4.4 seconds

Step-by-step explanation:

It hits the ground when the height is equal to zero

This occurs just before 4.5 seconds

t = 4.4 seconds

Answer:

6 cm

Step-by-step explanation:

The volume of a cone = (1/3) πr²h

72π = (1/3) π r² 6

72 = (1/3) r² 6

Divide both sides by 6

12 = (1/3) r²

Multiply both sides by 3

36 = r²

So r (radius) = 6 cm

Answer:

a. Smart Dot Company: C = 12 + 0.5·t

Communications Plus: C = 2.5·t

b. Please find attached the required tables created using MS Excel cell function tool

c. Please find attached the graph of both relationship created on the same grid with

Step-by-step explanation:

a. The monthly cost of the Smart Dot Company = $12

The hourly cost for internet use on Smart Dot Company = $0.50

The hourly cost of using the Communications Plus = $2.50

Therefore, the total monthly cost, C, for the duration of hours used, t, is given as follows;

Smart Dot Company: C = 12 + 0.5·t

Communication Plus: C = 2.5·t

b. The table of values are created using MS Excel as follows;

[tex]\begin{array}{ll}Smart \ Dot \ Company&\\Time \ (hours)&Cost \ (dollars)\\0&12\\2&13\\4&14\\6&15\\8&16\\10&17\end{array}[/tex]    [tex]\begin{array}{ll}Communications\ \ Plus&\\Time \ (hours)&Cost \ (dollars)\\0&0\\2&5\\4&10\\6&15\\8&20\\10&25\end{array}[/tex]

c. Please find attached the graph of both relationship created on the same grid with MS Excel

[tex]\\ \qquad\quad\sf\longmapsto m=8+n[/tex]

[tex]\\ \qquad\quad\sf\longmapsto m-n=8[/tex]

if m=1

[tex]\\ \qquad\quad\sf\longmapsto n=m-8=1-8=-7[/tex]

if n=1

[tex]\\ \qquad\quad\sf\longmapsto m=8+1[/tex]

[tex]\\ \qquad\quad\sf\longmapsto m=9[/tex]

9514 1404 393

Answer:

  A.  264 mi³

Step-by-step explanation:

The area of the right triangular base is ...

  A = 1/2bh

  A = 1/2(6 mi)(8 mi) = 24 mi²

Then the volume of the prism is ...

  V = Bh . . . . . where B is the base area and h is the distance between bases

  V = (24 mi²)(11 mi) = 264 mi³

Answer:

its c 120in

Step-by-step explanation:

The perimeter of the triangle is,

⇒ 138 in.

A triangle is a three sided polygon, which has three vertices and three angles which has the sum 180 degrees.

Given that;

The hypotenuse of a right triangle is 52 in.

And, One leg of the triangle is 8 in. more than twice the length of the other.

Hence, We get;

Lengths of legs are,

⇒ x

And, ⇒ 8 + 2x

Hence, We can formulate;

⇒ 52² = x² + (2x + 8)²

⇒ 2704 = x² + 4x² + 64 + 24x

⇒ 5x² + 24x - 2640 = 0

⇒ x = 20 and x = - 132/5

For perimeter;

Take x = 20

Hence, The perimeter of the triangle is,

⇒ 52 + x + (2x + 8)

⇒ 52 + 20 + (2 × 20 + 8)

⇒ 52 + 20 + 48

⇒ 138 in.

Thus, The perimeter of the triangle is,

⇒ 138 in.

Learn more about the triangle visit;

brainly.com/question/1058720

#SPJ7

Answer:

C

Step-by-step explanation:

First, let's say 4³ is a and 5⁻² is b. We know that (a/b)ⁿ = aⁿ/bⁿ for any n, so

(a/b)⁵ = a⁵/b⁵

=  (4³)⁵ /(5⁻²)⁵

Next, one power rule states that (4³)⁵ = 4 ⁽³ˣ⁵⁾ = 4¹⁵ and (5⁻²)⁵ = 5 ⁽⁻²ₓ⁵⁾=5⁻¹⁰, so

(4³)⁵ /(5⁻²)⁵ = 4¹⁵ / 5⁻¹⁰

Next, anything to a negative power (e.g. x⁻ⁿ) is equal to 1 over the absolute value of the power, so x⁻ⁿ = 1/xⁿ. Applying that here, we can say that

5⁻¹⁰ = 1/5¹⁰

4¹⁵ / 5⁻¹⁰ = 4¹⁵ / (1/5¹⁰) = (4¹⁵/1) / (1/5¹⁰) = 4¹⁵ * 5¹⁰

Answer:

c. 256π/3 units^3

Step-by-step explanation:

Recall that the volume V of a sphere with radius r is given as

V = 4 /3πr3

Hence from the image given, the radius of the sphere which is the distance from the center to any point on the circumference is 4 units hence the volume

V = 4/3 * π * 4^3

= 4/3 * π * 64

= 4*64/3 * π

= 256π/3 units^3

Option c is right

[tex]A = \begin{bmatrix}1&2\\1&1\end{bmatrix} \implies A^{-1} = \dfrac1{\det(A)}\begin{bmatrix}1&-1\\-2&1\end{bmatrix} = \begin{bmatrix}-1&1\\2&-1\end{bmatrix}[/tex]

where det(A) = 1×1 - 2×1 = -1.

[tex]B = \begin{bmatrix}0&-1\\1&2\end{bmatrix} \implies B^{-1} = \dfrac1{\det(B)}\begin{bmatrix}2&1\\-1&0\end{bmatrix} = \begin{bmatrix}2&1\\-1&0\end{bmatrix}[/tex]

where det(B) = 0×2 - (-1)×1 = 1. Then

[tex]B^{-1}A^{-1} = \begin{bmatrix}2&1\\-1&0\end{bmatrix} \begin{bmatrix}-1&1\\2&-1\end{bmatrix} = \begin{bmatrix}-1&3\\1&-2\end{bmatrix}[/tex]

On the other side, we have

[tex]AB = \begin{bmatrix}1&2\\1&1\end{bmatrix} \begin{bmatrix}0&-1\\1&2\end{bmatrix} = \begin{bmatrix}2&3\\1&1\end{bmatrix}[/tex]

and det(AB) = det(A) det(B) = (-1)×1 = -1. So

[tex](AB)^{-1} = \dfrac1{\det(AB)}\begin{bmatrix}1&-3\\-1&2\end{bmatrix} = \begin{bmatrix}-1&3\\1&-2\end{bmatrix}[/tex]

and both matrices are clearly the same.

More generally, we have by definition of inverse,

[tex](AB)(AB)^{-1} = I[/tex]

where [tex]I[/tex] is the identity matrix. Multiply on the left by A ⁻¹ to get

[tex]A^{-1}(AB)(AB)^{-1} = A^{-1}I = A^{-1}[/tex]

Multiplication of matrices is associative, so we can regroup terms as

[tex](A^{-1}A)B(AB)^{-1} = A^{-1} \\\\ B(AB)^{-1} = A^{-1}[/tex]

Now multiply again on the left by B ⁻¹ and do the same thing:

[tex]B^{-1}\left(B(AB)^{-1}\right) = (B^{-1}B)(AB)^{-1} = B^{-1}A^{-1} \\\\ (AB)^{-1} = B^{-1}A^{-1}[/tex]

Answer:

D) 9:00 am

Step-by-step explanation:

Because 9:00 is the midpoint of 7 and 12

Answer:

Step-by-step explanation:

[tex]\frac{3}{4} x \frac{8}{3} =2[/tex]

Answer: The chosen topic is not meant for use with this type of problem. Try the examples below.

x

=

2

,

y

=

1

x

=

9

,

y

=

10

x

=

9

,

y

=

4

Answer:

b) 7.89*10^4

c) 3.15*10^3

Step-by-step explanation:

2-42)

the coefficient in scientific notation (the number that is not 10^x) has to be greater or equal to 1 and less than 10. so c and b are incorrect.

b) 0.789*10^5

c) 31.5*10^2

b) 0.789*10^5

in order to make 0.789 greater than 1, I would just multiply it by 10. shown below

=0.789*10*10*10*10*10

=7.89*10*10*10*10

=7.89*10^4

c) 31.5*10^2

same concept but this time divide by 10 to make 3.15 which will add another *10 to the exponent

=31.5*10*10

=3.15*10*10*10

=3.15*10^3

Answer:

Step-by-step explanation:

I forgot

Answer:

Following are the responses to the given question:

Step-by-step explanation:

The following relationships usually have a direct or inverse relationship, please indicate.

Answer:

A. x/5 - 6 > -4

Step-by-step explanation:

The graph shows that x > 10. We need to solve each of the inequalities. After we do, we see that A is the answer.

A. x/5 - 6 > -4

x/5 > 2

x > 10

Welp....there's your answer

It's very blurry can u retake it?

$\sf\underline\bold{Question:1-}$

A ball is thrown upwards and it goes to the height of 100meter and comes down. What is the net displacement?

$\sf\underline\bold{Solution}$

$\sf{According \: to\:the\: question,}$

Displacement for the above situation is 0. As we know, that displacement is the shortest path from the initial to the final point. Here, the initial and the final points are the same, and henceforth, it takes no time to travel. So the displacement is 0.

$\sf\underline\bold{Question:2-}$

An athlete completes one round of a circular track of diameter 200m in 30 seconds. Find the distance covered by the athlete at the end of 30 second.

$\sf\underline\bold{Solution:}$

$\sf\bold{Given\:parameters:}$

$\sf\small{☆The\:diameter\:of\:the\:circular\:track:200m}$

$\sf{Radius=}$ $\sf\dfrac{200}{2}$ → $\sf\underline{Radius = 100m}$

☆Time taken by an athlete to complete one round : 30 seconds.

$\space$

$\sf\bold{To\:find:}$

❍Distance travelled by an athlete in 30 seconds.

$\space$

❍ AND,Distance travelled by the athlete will be equal to the cumference of the circle.

$\space$

$\space$ $\space$ $\space$ $\space$ $\space$ $\space$ $\sf{So,}$

$\mapsto$ $\sf{Circumference\:of\:the\:circle: 2 πr}$

$\space$

$\mapsto$ $\sf{Circumference=2\times}$ $\sf\dfrac{22}{7}$ $\sf{\times 100}$

$\space$

$\mapsto$ Circumference of the circle : $\sf\dfrac{4400}{7}$

$\space$

[tex]\sf\underline\bold{∴Circumference = 628.57m}[/tex]

$\space$

||Therefore,The distance travelled in 30 seconds, by the athlete is 628.57m.||

0 = 1st answer

628.57 m = Question 2 answer.