A carnot engine has an efficiency of 50% when its sink temperature is 27°C. The temperature of source is: a) 300°C b) 327°C c) 273°C d) 373°C​

Answers

Answer 1
Answer:

327 degrees

Have a great day!


Related Questions

Where are spores located on a fern? 1. On the root systems 2. In the flowers of the ferns 3. On the underside of the fronds 4. In the capsule of the sporophyte

Answers

C

Because it shown me the same way that I was talking to her about her

The particles of a substance stay close together but slide past one another as they move. When thermal energy is removed from the substance, the particles are forced into fixed positions by their attraction to one another. What change in state has occurred?
O A. Gas to solid
O B. Liquid to solid
O C. Solid to liquid
O D. Gas to liquid​

Answers

Explanation:

The Answer is B.I think so may be it's wrong so kindly get any confirmation from your teacher about this

Which object has potential energy but not kinetic energy?

A.
A battery in a pair of headphones

B.
A person riding an elevator upward

C.
A person climbing a ladder

D.
A car that is slowing down

Answers

Answer:

A.

A battery in a pair of headphones

Explanation:

Potenial energy - the energy possessed by a body by virtue of its position relative to others, stresses within itself, electric charge, and other factors.

un litro de un gas es calentado a presión constante desde 20°C hasta 60°C que volumen final ocupará dicho gas? ​

Answers

Answer:

Final volume, V2 = 3 Litres

Explanation:

Given the following data;

Initial volume, V1 = 1 litre

Initial temperature, T1 = 20°C

Final temperature, T2 = 60°C

To find the final volume, we would use Charles' law;

Charles states that when the pressure of an ideal gas is kept constant, the volume of the gas is directly proportional to the absolute temperature of the gas.

Mathematically, Charles is given by;

V1/T1 = V2/T2

Making V2 as the subject formula, we have;

V1T2 = V2T1

V2 = (V1T2)/T1

Substituting into the formula, we have;

V2 = (1 * 60)/20

V2 = 60/20

Final volume, V2 = 3 Litres

Earth changes all the time making it a __ planet.

Answers

The answer is Dynamic.
“making is a Dynamic planet”


20 kg rodsis on the edge of a 80 m high de What is the rodes gracional potencial energy?

Answers

Answer:

Gpe = 15680 Joules

Explanation:

Gravitational potential energy (GPE) is an energy possessed by an object or body due to its position above the earth.

Mathematically, gravitational potential energy is given by the formula;

G.P.E = mgh

Where;

G.P.E represents potential energy measured in Joules.

m represents the mass of an object.

g represents acceleration due to gravity measured in meters per seconds square.

h represents the height measured in meters.

Given the following data;

Mass = 20 kg

Height = 80 m

We know that acceleration due to gravity is equal to 9.8 m/s²

To find the gravitational potential energy;

Gpe = mgh

Gpe = 20 * 80 * 9.8

Gpe = 15680 Joules

Light of wavelength 530.00 nm is incident normally on a diffraction grating, and the first‑order maximum is observed to be 33.0∘ from the normal. How many slits per millimeter are marked on the grating?

Answers

Answer:

1028 slits/mm

Explanation:

We are given that

Wavelength of light, [tex]\lambda=530nm=530\times 10^{-9} m[/tex]

1nm=[tex]10^{-9} m[/tex]

[tex]\theta=33^{\circ}[/tex]

n=1

We have to find the number of slits per mm are marked on the grating.

We know that

[tex]dsin\theta=n\lambda[/tex]

Using the formula

[tex]dsin33^{\circ}=1\times 530\times 10^{-9}[/tex]

[tex]d=\frac{530\times 10^{-9}}{sin33^{\circ}}[/tex]

[tex]d=9.731\times 10^{-7} m[/tex]

1m=[tex]10^{3}mm[/tex]

[tex]d=9.731\times 10^{-7}\times 10^3[/tex]mm

[tex]d=0.0009731mm[/tex]

Number of slits=[tex]\frac{1}{d}[/tex]

Number of slits=[tex]\frac{1}{0.0009731}[/tex]/mm

Number of slits=1028/mm

Hence, 1028 slits/mm are marked on the grating.

Answer:

1027.6 lines per mm.

Explanation:

wavelength = 530 nm

order, m= 1

Angle = 33 degree

Let the slits per mm is 1/d.

So,

[tex]m \lambda = d sin A\\\\1\times 530\times 10^{-6} = d sin 33\\\\\frac{1}{d} = 1027.6 lines per mm[/tex]

A 20-N force acts on a 5-kg object at rest. How fast will
the object accelerate on a frictionless surface?
A. 15 m/s^2
B. 25 m/s^2
C. 4 m/s^2
D. 100 m/s^2

Answers

Answer:

C.

Explanation:

Force = Mass * Acceleration

So 20 = 5* Acceleration

4 = Acceleration

The acceleration of the object is 4 m/s².

To find the acceleration, the given values are:

Force = 20 N

Mass = 5 kg

Define acceleration.

Definition:

     As it was given as the values of  Force and mass, here acceleration definition depends on the Newton's second law of motion.

Using the second law of motion, the force will be equal to the product of the mass and the acceleration.

As formula,

                               F = ma Newton

Here, to find acceleration,

                              a =f/ m

Substituting the values,

                              = 20 / 5

                            a = 4m/s².

So, the acceleration was 4 m/s². The Option C is the correct answer.

Learn more about acceleration,

https://brainly.com/question/12550364

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25)Two forces are acting on a block in opposite directions as shown in the figure above
(a) Calculate the net force acting on the block.
(b) In which direction will the net force tend to move the object?
(c) Will any other force try to oppose the motion of the block? ​

Answers

[tex]\boxed{ \sf{Answer}} [/tex]

____________________

(a) A = 5 kgwt

B = 10 N

First convert 5 kgwt to N,

[tex]5 \times 9.8 \\ = 49 \: N[/tex]

Net force [the forces are acting in 2 opposite directions]

[tex]A - B \: \\ = 49 - 10 \\ = 39 \: N[/tex]

____________________

(b) Since, the force is greater by A ↦the block will move towards B, i.e, to the right.

____________________

(c) Frictional force will try to oppose the motion of the block but since A has greater force than B, the frictional force will be resisted.

____________________

ʰᵒᵖᵉ ⁱᵗ ʰᵉˡᵖˢ ツ

꧁❣ ʀᴀɪɴʙᴏᴡˢᵃˡᵗ2²2² ࿐

An object is free falling near the surface of the earth. At a certain instant in time, it is falling downward at a rate 25.0 m/s. After 2.5 seconds, what are its acceleration and velocity?

Answers

Answers:

acceleration = 9.81 m/s^2velocity = 49.5 m/s

The values are approximate.

==========================================================

Explanation:

When near the surface of the earth, the acceleration of gravity is roughly 9.81 m/s^2. This means that after each second passes, the velocity increases by roughly 9.81 m/s.

After 2.5 seconds, the velocity increases by 2.5*9.81 = 24.525 m/s = 24.5 m/s

If it was already going 25.0 m/s, then it bumps up to 25.0+24.5 = 49.5 m/s which is also approximate.

The acceleration of gravity stays the same when the object is close to the surface of the earth, so it stays at roughly 9.81 m/s^2

Side note: I'm ignoring air resistance (aka air friction or drag) since that greatly complicates things, and we would need to know the shape and surface area of the object. The material type would also be relevant info as well.

What what is the change in internal energy if 500 joule of heat is added to a system and 125 joule of work are done on a system

Answers

Answer:

DU = 375 Joules

Explanation:

Given the following data;

Quantity of heat = 500 Joules

Work done = 125 Joules

To find the change in internal energy;

Mathematically, the change in internal energy of a system is given by the formula;

DU = Q - W

Where;

DU is the change in internal energy.Q is the quantity of energy.W is the work done.

Substituting into the formula, we have;

DU = 500 - 125

DU = 375 Joules

Cuộn dây có N = 1000 vòng, mỗi vòng có diện tích S = 20 cm2 đặt trong một từ trường đều. Trục của cuộn dây song song với vectơ cảm ứng từ của từ trường. Cho độ lớn B biến thiên, người ta thấy có suất điện động cảm ứng eC = 10V được tạo ra. Độ biến thiên cảm ứng từ là bao nhiêu trong thời gian ∆t = 10-2 s

Answers

sorry i don’t understand would love to help tho !

16 100 g of water at 25 °C is poured into an insulating cup. 50 g of ice at 0 °C is added to the water.
The water is stirred until the temperature of the water has fallen to 0°C.
18 g of ice remains unmelted.
The specific heat capacity of water is 4.2 J /g °C.
Which value does this experiment give for the specific latent heat of fusion of ice?

Answers

Answer:

Q = Q

mcT = ml

100 x 4.2 x 25 = (50-18) l

l = 328

*Hope it helps*

The specific latent heat of fusion of the melted ice is 328.13 J/kg.

Conservation of energy

The specific latent heat of fusion of the melted ice is determined by applying the principle of conservation of energy as shown below;

Heat lost by the water = Heat gained by the ice

McΔθ = mL

where;

c is specific heat capacity of waterL is pecific latent heat of fusion of icem is mass of melted ice = 50 g - 18 g = 32 g

(100)(4.2)(25) = (32)L

32L = 10500

L = 328.13 J/kg

Thus, the specific latent heat of fusion of the melted ice is 328.13 J/kg.

Learn more about heat capacity here: https://brainly.com/question/16559442

A sample of nitrogen gas is inside a sealed container. The volume of the container decreases while the temperature is kept constant. This is a ________ process.

a) isothermal
b) constant-volume
c) adiabatic
d) isobaric

Answers

I guess it’s d) isobaric mate correct me if I am wrong :D

what do you mean by supplementary quantities and its unit?​

Answers

~Solution :-Supplementary Quantities are geometrical quantities of circle and sphere. Supplementary are the units not still classified either as base or derived.

$ \large\boxed{ \sf \red{More ~Info :}}$

The units of supplementary quantities are dimensionless units.

[tex] \\ [/tex]

Imagine using brainly LOL COULDNT BE ME XD

Answers

Answer:

LOL! couldnt be me either bestieeeee

Answer:

-_-

Explanation:

i dont know What was XD??

determine the metacentric height of a cylinder of 4 m diameter and height of 4m floating in water with its axis vertical, if period of oscillation is 6 seconds

Answers

Answer:

-0.383 m

Explanation:

Diameter of cylinder = 4m  therefore  r = 2

height of cylinder ( H ) = 4 m

specific gravity = 0.6 ( assumed )

depth of immersion = 'h'

Determine the metacentric height

weight of cylinder in water = water displaced

= 0.6 * 1000 * πr^2* H = 1000 * πr^2* h

= 0.6 * 4 = h

∴ h = 2.4 m

hence the depth of center of buoyancy from free space = h /2 = 1.2 m

The metacentric height can be calculated using the formula below

Gm = Io / Vsubmerged  - BG

attached below is the remaining solution

1. How much heat energy ( Q ) is required to heat 2.0 kg of copper from 30.0 oC to 80.0 oC?

Answers

Answer:

Heat capacity, Q = 38500 Joules

Explanation:

Given the following data;

Mass = 2 kg

Initial temperature, T1 = 30°C

Final temperature, T2 = 80°C

Specific heat capacity of copper = 385 J/Kg°C

To find the quantity of heat required;

Mathematically, heat capacity is given by the formula;

[tex] Q = mcdt [/tex]

Where;

Q represents the heat capacity or quantity of heat.

M represents the mass of an object.

C represents the specific heat capacity of water.

dt represents the change in temperature.

dt = T2 - T1

dt = 80 - 30

dt = 50°C

Substituting the values into the formula, we have;

[tex] Q = 2 * 385*50[/tex]

Heat capacity, Q = 38500 Joules

What is the difference between heat capacity and specific heat capacity? I want the meaning please.

Answers

Answer:

The heat capacity of a body is defined as the heat required to raise it's temperature by me degree or one kelvin.while specific heat capacity of a substance is defined as the heat required to the temperature of a unit mass of it through one degree or one kelvin.

I hope it helps

An electron experiences a downward force of 12.8×10-19 N while traveling in a magnetic field of 8×10-5 T west, what is the magnitude of the velocity?

Answers

Answer:

[tex]v=10^5\ m/s[/tex]

Explanation:

Given that,

Magnetic force acting on an electron, [tex]F=12.8\times 10^{-19}\ N[/tex]

The magnitude of the magnetic field,[tex]B=8\times 10^{-5}\ T[/tex]

We need to find the magnitude of the velocity. We know that the magnetic force is given by :

[tex]F=qvB[/tex]

Where

v is the velocity

So,

[tex]v=\dfrac{F}{qB}\\\\v=\dfrac{12.8\times 10^{-19}}{1.6\times 10^{-19}\times 8\times 10^{-5}}\\\\v=10^5\ m/s[/tex]

So, the magnitude of velocity is[tex]10^5\ m/s[/tex].

A vector points -43.0 units along the x axis, and 11.1 units along the y axis. Find the Direction of the vector.

Answers

Answer:

Explanation:

The direction of the vector implies only its angle, not its magnitude. The direction of the vector is found in

[tex]tan^{-1}(\frac{y}{x})[/tex] so

[tex]tan^{-1}(\frac{11.1}{-43.0})=-14.5[/tex] but since we are in QII (where x is negative and y is positive) we have to add 180 to this number to get a direction of 165.5 degrees

newtons second law lab report link

Answers

Answer:

ghittu iihg उह्स उउह्स उग्य्किव जिक्ह्ब

A convex mirror of radius of curvature 1.6 m has an object placed at a distance of 1.0 m from it. Find the position of image and the magnification.​

Answers

Answer:

The image is formed at 0.44 m in front of the mirror

magnification (M) = 0.44

Explanation:

Applying, mirror formular

1/f = (1/u)+(1/v).................... Equation 1

Where f = Focal length of the convex mirror, u = object distance, v = image distance.

Using the real is positive convection,

From the question,

Given: f = -1.6/2 = -0.8 m( The focal length of a convex mirror is vitual), u = 1.0 m

Substitute these values into equation 1

-1/0.8 = (1/v)+(1/1)

Solve for v

1/v = 1.25+1

1/v = 2.25

v = 1/2.25

v = 0.44 m

Hence the image is formed at 0.44 m in front of the mirror

Magnification (M) = v/u

m = 0.44/1

m = 0.44

A blackbody radiator was expected to give off energy of increasing frequency
as its temperature increased. Which of the following ideas provided an
important step toward understanding why this was not observed?
A. Light is quantized and must be absorbed as a unit.
B. Electrons can act as both waves and particles.
C. Matter is quantized and cannot be broken down.
D. Large objects can be viewed as acting as waves.

Answers

Answer:

B.

Explanation:

Makes more sense to me

The Indianapolis speedway consists of a 2.5 mile track having four turns, each 0.25 mile long and banked at 9 12'

Answers

Answer: Your question is missing below is the question

Question : What is the no-friction needed speed (in m/s ) for these turns?

answer:

20.1 m/s

Explanation:

2.5 mile track

number of turns = 4

length of each turn = 0.25 mile

banked at 9 12'

Determine the no-friction needed speed

First step : calculate the value of R

2πR / 4 =  πR / 2

note : πR / 2 = 0.25 mile

∴ R = ( 0.25 * 2 ) / π

      = 0.159 mile ≈ 256 m

Finally no-friction needed speed

tan θ = v^2 / gR

∴ v^2 = gR * tan θ

 v = √9.81 * 256 * tan(9.2°)  = 20.1 m/s

Mike lives in the northern United States minnesota and nick lives in the southern United States Louisiana. When they both feel insulted by the same individual, nick will be more

Answers

Complete question is;

Mike lives in the northern United States (in Minnesota) and Nick lives in the southern United States (Louisiana). When they both feel insulted by the same individual, Nick will be more likely to have a(n) ________ cortisol response and show ________ levels of physical aggression.

Answer:

- A hyper cortisol response

- higher levels of physical aggression

Explanation:

In study of hormones in the human body, it has been discovered that cortisol is a stress inducing hormone. Now, if they are in the summer when it is hot, it has been proven that's when the cortisol hormone circulates in a very large manner in the blood. This leads to frustration and as well possibly physical aggression.

Nick will be more likely to have a(n) hyper cortisol response and show higher levels of physical aggression.

What is cortisol?

Cortisol has been identified as a stress-inducing hormone in studies of hormones in the human body.

Mike lives in the northern United States (in Minnesota) and Nick lives in the southern United States (Louisiana).

When they both feel insulted by the same individual, Nick will be more likely to have a(n) hyper cortisol response and show higher levels of physical aggression.

Cushing syndrome is a condition characterized by elevated cortisol levels. This disorder is caused by your body producing too much cortisol.

Similar symptoms can occur after large doses of corticosteroids, thus this should be cleared out before testing for crushing syndrome.

Cortisol has been identified as a stress-inducing hormone in studies of hormones in the human body. Now, if they are in the summer when it is hot.

It has been proved that the cortisol hormone circulates in the blood in a very significant amount. This causes irritation and, in some cases, physical aggressiveness.

Hence nick will be more likely to have a(n) hyper cortisol response and show higher levels of physical aggression.

To learn more about cortisol refer to the link

https://brainly.com/question/7519944

If the mass of the Jupiter is 1.9*10 kg and radius is fbx loom what is acclerallon due to gravity on the supiter ?​

Answers

Answer:

[tex]g=25.92\ m/s^2[/tex]

Explanation:

Given that,

The mass of the Jupiter,[tex]M=1.9\times 10^{27}\ kg[/tex]

The radius of Jupiter,[tex]r=69,911\ km=69911\times 10^3 km[/tex]

We need to find the acceleration due to gravity on Jupiter. The formula is

[tex]g=G\dfrac{M}{r^2}[/tex]

Put all the values,

[tex]g=6.67\times 10^{-11}\times \dfrac{1.9\times 10^{27}}{(69911\times 10^3)^2}\\\\g=25.92\ m/s^2[/tex]

So, the value of acceleration due to gravity on the Jupiter is [tex]25.92\ m/s^2[/tex].

A wire, 20m long, is heated from a temperature of 5°C to 55°C. If the change in length is 0.020m, calculate the linear expansivity of the wire.​

Answers

Answer:

0.01998⁰C;¹

Explanation:

you can see all steps in photo

A mother is pulling a sled at constant velocity by means of a rope at 37°. The tension on the rope is 120 N. Mass of children plus sled is 55 kg. The mother has a mass of 61 kg.
a) Draw FBD for the sled with the kids as one object
b) Draw FBD for the mother
c) Find the normal force on the sled and on the mother
d) Find the kinetic friction acting on the sled and the static friction acting on the mother
e) Find the coefficient of kinetic friction for the sled

Answers

Answer:

Please find the complete solution in the attached file.

Explanation:

A basketball is shot by a player at a height of 2.0 m. The initial angle
was 53° above horizontal. At the highest point the ball was travelling 6
m/s. If he scored (the ball went through the rim that is 3.00 m above the
ground), what was the player’s horizontal distance from the basket?

Answers

Answer:

The answer is "8.28 m".

Explanation:  

[tex]\to u \cos 53^{\circ}=6 \ \text{therefore the horizontal velocity is constant alaways}\\\\\therefore[/tex]

[tex]u= \frac{6 \times 5}{3}= \frac{30}{3}= 10\ \frac{m}{s}\\\\[/tex]

In the projectfile when vertical displacement is 1 then 5 m comes at farther sides

Using  

[tex]S=ut-\frac{1}{2} gt^2\\\\1=u\sin 53^{\circ}\times t-5t^2\\\\1=8t-5t^2\\\\5t^2-8t+1=0\\\\ t=\frac{8\pm \sqrt{64-20}}{10} \\\\=\frac{8\pm 2\sqrt{11}}{10} \\\\t_2=\frac{8+2\sqrt{11}}{10} \\\\[/tex]

[tex]Distance=u \cos 53^{\circ}\times t_2\\\\[/tex]

               [tex]=6 \times \frac{8\pm 2\sqrt{11}}{10} \\\\=\frac{24\pm 6\sqrt{11}}{5} \\\\= 8.28 \ m[/tex]

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