(Ch3ch2)2choh oxidize with k2cr2o7?

Explanation:

the answer is in the image above

Answer:

%C = 60.9%; %H = 15.4%; %N = 23.7%

Explanation:

Step 1: Given data

Step 2: Calculate the percent composition of this compound

To calculate the percent by mass of any element (E), we will use the following expression.

%E = mE/m × 100%

%C = 7.34 g/12.04 g × 100% = 60.9%

%H = 1.85 g/12.04 g × 100% = 15.4%

%N = 2.85 g/12.04 g × 100% = 23.7%

Answer:

His results will be skewed because there was more water than stock solution. Which would cause the percentage solution to be less than 50% therefore the density would be less than the actual value.

Explanation:

The solution will have percentage less than that of 50%. Therefore the density would be less than the actual value.

Suppose there should be 50 mL of the solution, and he added 60 mL. So 10 mL of the solution is added more.

Suppose the mass of the solute is m.

Originally, the density is = [tex]$\frac{m}{50}$[/tex]     [tex]\left(\frac{\text{mass}}{\text{volume}}\right)[/tex]

Now after adding extra 10 mL , the density becomes [tex]$\frac{m}{60}$[/tex].

Therefore, [tex]$\frac{m}{50}>\frac{m}{60}$[/tex]

So the density decreases when we add more solution.

Answer:

Which type of chemistry studies the chemical reactions that occur in the human body? .

biochemistry

The correct answer is biochemistry.

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the identity of element remains same

1 NaCl + 1 HCl ➡️ 1 NaCl + Water (H2O) .

Answer:

A range of organic molecules can undergo combustion. Pyridine (C5H5 combustion in the unbalanced reaction shown below wtar o 4 CsH5N + O2 +H2O + CO2 + NO a) Write the balanced equation. (2 points) # 41 CH N +170 70 the flow, t- b) Find the percent yield for the reaction if 10.0 g of pyridine dioxide. (2 points)

Explanation:

hope this helps!

Answer:

Etching is used to reveal the microstructure of the metal through selective chemical attack. It also removes the thin, highly deformed layer introduced during grinding and polishing. ... The specimen is etched using a reagent.

Explanation:

hope it was helpful.....

Answer:

Explanation:

This is because, Blue color highest frequency of energy after Violet and Indigo.

Answer:

See explanation

Explanation:

We define the formal charge on an atom in a molecule as the charge it carries assuming that electrons in all chemical bonds of the molecule were shared equally between atoms irrespective of the electronegativity of each atom.

The formula for calculating the formal charge on an atom in a molecule is;

Formal Charge = [number of valence electrons on neutral atom] – [(number of lone electron pairs) + (½ number of bonding electrons)] ·

The formal charge on the two nitrogen atoms in diazomethane is obtained as follows;

Middle nitrogen atom = 5 – 8/2 – 0 = +1

Last nitrogen atom = 5 – 4/2 – 4 = –1

The Lewis structure of the molecule is shown in the image attached.

Answer:

carbohydrates are simple sugars which can be broken down to form 3 sugars.

which are , (maltose) (fructose) & (glucose)

Answer:

Option A. 11

Explanation:

We'll begin by calculating the concentration of Hydroxide ion in the solution. This can be obtained as follow:

KOH (aq) —> K⁺(aq) + OH¯(aq)

From the balanced equation above,

1 mole of KOH produced 1 mole of OH¯.

Therefore, 1×10¯³ M KOH will also produce 1×10¯³ M OH¯.

Next, we shall determine the pOH of the solution. This can be obtained as follow:

Concentration of Hydroxide ion [OH¯] = 1×10¯³ M

pOH =?

pOH = –Log [OH¯]

pOH = –Log 1×10¯³

pOH = 3

Finally, we shall determine the pH of the solution. This can be obtained as follow:

pOH = 3

pH =?

pH + pOH = 14

pH + 3 = 14

Collect like terms

pH = 14 – 3

pH = 11

Therefore, the pH of the solution is 11

Answer:The law of conservation of mass states that in a chemical reaction mass is neither created nor destroyed. ... The carbon atom changes from a solid structure to a gas but its mass does not change. Similarly, the law of conservation of energy states that the amount of energy is neither created nor destroyed.

Explanation:

Answer:

tge answer is a

Explanation:

I'm smart like that

Answer:

D

Explanation:

8oz=1cup

Xoz=1/4cup

cross multiply

Xoz=8×1/4=2

2oz=1/4cup

1oz=2T

2oz=x

cross multiply

×=2×2=4T

The cup of butter, number of tablespoons and ounces of butter are all in direct proportion with one another. The interpretation of the information provided is:

(b). The information provided gives the conversion factor 8oz/1 cup.

Given that:

[tex]1\ recipe = \frac{1}{4}\ cup[/tex]

[tex]1\ oz = 2T[/tex]

[tex]8\ oz = 1\ cup[/tex]

Multiply both sides of [tex]1\ oz = 2T[/tex] by 8

[tex]8 \times 1oz = 8 \times 2T[/tex]

[tex]8 oz = 16T[/tex]

Substitute 8oz for 1 cup in: [tex]1\ recipe = \frac{1}{4}\ cup[/tex]

[tex]1\ recipe = \frac{1}{4} \times 8oz[/tex]

Substitute [tex]8 oz = 16T[/tex]

[tex]1\ recipe = \frac{1}{4} \times 16T[/tex]

[tex]1\ recipe = 4T[/tex]

The interpretations are as follows:

Hence, (b) is correct

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Answer:

Classify each structure according to its functional class.

Compound A contains a carbonyl bonded to two alkyl groups.

Compound B contains an oxygen bonded to two alkyl groups.

Compound C contains a carbonyl bonded to propyl and N H C H 3.

Compound D is a nitrogen bonded to three alkyl groups.

Explanation:

Compound A contains a carbonyl bonded to two alkyl groups.

-C=O group is called a carbonyl group.

If it is present between two alkyl groups then, it is a ketone.

Compound B contains oxygen bonded to two alkyl groups.

Compound B is an example of an ether molecule.

Compound C contains a carbonyl bonded to propyl and N H C H 3.

Compound C is C3H7-CO-NHCH3 which is an amide molecule.

Compound D is nitrogen bonded to three alkyl groups.

This is an example of a tertiary amine group.

Answer:

Its D Are in random motion

i hope it will help you if not soo sorry :)

Answer:

2-isopropyl-4-methylphenol.

Explanation:

Hey there!

In this case, according to the given information, it turns out possible for us to assign the appropriate IUPAC name of the given compound, by considering that the phenol stands for the parent chain and we have isopropyl methyl radicals which the former is called first due to the alphabet consideration.

In such a way, the name would be 2-isopropyl-4-methylphenol.

Regards!

Explanation:

this is a single Replacement Reaction, so Na and Cl will form a bond.

Answer: The final temperature will be [tex]52.74^oC[/tex]

Explanation:

Calculating the heat released or absorbed for the process:

[tex]q=m\times C\times (T_2-T_1)[/tex]

In a system, the total amount of heat released is equal to the total amount of heat absorbed.

[tex]q_1=-q_2[/tex]

OR

[tex]m_1\times C\times (T_f-T_1)=-m_2\times C\times (T_f-T_2)[/tex] ......(1)

where,

C = heat capacity of water = [tex]4.184J/g^oC[/tex]

[tex]m_1[/tex] = mass of water of sample 1 = 100.0 g

[tex]m_2[/tex] = mass of water of sample 2 = 71.0 g

[tex]T_f[/tex] = final temperature of the system = ?

[tex]T_1[/tex] = initial temperature of water of sample 1 = [tex]27^oC[/tex]

[tex]T_2[/tex] = initial temperature of the water of sample 2 = [tex]89.0^oC[/tex]

Putting values in equation 1, we get:

[tex]100.0\times 4.184\times (T_f-27)=-71.0\times 4.184\times (T_f-89)\\\\171T_f=9019\\\\T_f=\frac{9019}{171}=52.74^oC[/tex]

Hence, the final temperature will be [tex]52.74^oC[/tex]

Answer:

1. Draw only the valence electrons.

2. Give every element main group element (except hydrogen) an octet of electrons.

3. Give each hydrogen two electrons.

Explanation:

Lewis structures are used to describe the arrangement or configurations of the valence electrons of molecules and polyatomic ions involved in electronic bonding. A Lewis structure consists of the symbols of the elements in the molecule surrounded by dots with each dot representing each of the elements valence electrons. Also, the electrons shared between two elements are shown by dots between the two elements and these electrons are known as shared electron pairs. The valence electrons on atom that is not involved in bonding is known as lone pairs.

The three general rules for drawing Lewis structures are:

1. Draw only the valence electrons. Only the valence electrons of the atoms of elements are shown since they are the only electrons involved in chemical bonding.

2. Give every element main group element (except hydrogen) an octet of electrons. The complete eight valence electrons of the noble gases is associated with their stability. Thus, the main group elements show a tendency to form enough bonds to obtain eight valence electronsmin order to achieve stability. This is known as the octet rule. However, since the maximum number of valence electrons for elements in the first period of the period table is two, the noble gas helium has completely-filled valence shell containing two electrons known as a duplet. Hydrogen belongs to the first period and is therefore an exception tomthe octet rule.

3. Give each hydrogen two electrons. Hydrogen attains a duplet structure in accordance with the structure of helium

Answer:

1x10^-6

Explanation:

Answer:

The answer is consumers

Answer:

Consumers are the group of organisms that has the least biomass and energy.

Answer:

.This is because gravity pulls down harder on the heavier one, which increases its friction with the floor

Mark me as Branliest

Answer:

a. 3-brumo - 3-methylhexane

Explanation:

Alkyl Halides can undergo substitution reactions. Nucleophiles are electron rich species and has negative charge while Electrophiles are electron deficient species which carry positive charge. Alkyl halide which have polar carbon atom are electrophiles.

Answer:

b . uranium, It is not a renewable resource.

Explanation:

[tex]2H_2O_2 \rightarrow 2H_2O + O_2[/tex]

First convert the amount of water into moles:

360 g H2O × [tex]\left(\dfrac{1\:\text{mol}H_2O}{18.015\:\text{g}H_2O}\right)[/tex]

[tex] = 20. \:\text{mol}H_2O[/tex]

Now let's calculate the number of moles of O2 gas produced.

20 mol H2O × [tex]\left(\dfrac{1\:\text{mol}O_2}{2\:\text{mol}H_2O}\right)=10\:\text{mol}O_2[/tex]

The volume of gas at 10°C and 5 atm can be found using the ideal gas law:

[tex]PV=nRT[/tex]

[tex]V= \dfrac{nRT}{P}[/tex]

[tex]= \dfrac{(10)(0.082)(283)}{(5)}=46.4\:L[/tex]

Answer:

The heat change in calories for condensation of 11.0 g of steam at 100°C is 5930 calories

Explanation:

Latent heat of condensation is the heat released when one mole of steam or water vapor condenses to form liquid droplets. The heat of condensation of water at 100° C is about 2,260 kJ/kg, which is equal to 40.68 kJ/mol. Since condensation of steam and vaporization of water occur at the same temperature and require the same amount of energy to occur, the heat of condensation is exactly equal to the heat vaporization, but has the opposite sign. In the vaporization, heat energy is absorbed by the substance, whereas in condensation heat energy is released by the substance.

The specific latent heat of vaporization of steam at 100° C = 40.68 kJ/mol

Number of moles of moles of water in 11.0 g of steam = mass/ molar mass

Molar mass of water = 18.0 g/mol

Number of moles of steam = 11.0 g / 18.0 g/mol = 0.61 moles

Heat released = 40.68 K/mol × 0.61 moles = 24.815 kJ

Converting to kcal by dividing 24.815 kJ by 4.184 = 5.93 kcal or 5930 calories

Therefore, the heat change in calories for condensation of 11.0 g of steam at 100°C is 5930 calories

Answer:

Amount of water

The thermometer

Explanation

In an experiment, there is always a dependent variable and an independent variable. The independent variable is manipulated and its effect on the dependent variable is observed.

The control is that factor in the experiment that must remain constant so that effect of the independent variable on the dependent variable can be observed.

In this case, the independent variable is the amount of sodium chloride while the dependent variable is the temperature at which the solution boils.

The controls must be the amount of water which must be held constant and the same thermometer used to measure the temperature so that the effect of the amount of sodium chloride on the temperature of the solution can be studied.

The following are the controls in the experiment:

The beaker with 100 mL of water without any sodium chloride.

The temperature of the Bunsen burner.

The type of thermometer used.

The control(s) in the experiment are the beaker with 100 mL of water without any sodium chloride. This beaker is used to compare the boiling points of the other beakers, which have different amounts of sodium chloride added.

The control beaker ensures that any differences in boiling point are due to the amount of sodium chloride added, and not to other factors, such as the temperature of the Bunsen burner or the type of thermometer used.

The other factors that could affect the boiling point of water, such as the humidity of the air or the altitude, are kept constant in the experiment.

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