Answer:
Frequency = 24 × 10⁸ Hz
Explanation:
Given the following data;
Speed = 3 × 10⁸ m/s
Wavelength = 0.125 meters
To find the frequency of the electromagnetic wave;
Mathematically, the speed of a wave is given by the formula;
Speed = Wavelength × frequency
Substituting into the formula, we have;
3 × 10⁸ = 0.125 × frequency
Frequency = (3 × 10⁸)/0.125
Frequency = 24 × 10⁸ Hz
What information does the period number give about an atom?
Answer:All of the elements in a period have the same number of atomic orbitals. For example, every element in the top row (the first period) has one orbital for its electrons. All of the elements in the second row (the second period) have two orbitals for their electrons.Explanation:
Answer:
It tells us the principle quantum shell in which the element lies in. In other words, it shows the total number of electron shells the atom has
Capacitance (C) is measured in farads, where 1 farad is equivalent to 1 coulomb per volt. Resistance (R) is measured in ohms, and 1 ohm is equal to 1 volt per ampère. The coulomb is defined as the amount of charge passing when a current of 1 ampère flows for 1 second. What is the unit of RC expressed in its simplest form?
When fundamental units are combined, they result in derived units. RC (which means Resistance Capacitance) is a derived unit and its unit in the simplest form is Coulomb per Ampere (C/A)
Given that:
Capacitance (C) [tex]\to[/tex] Farads (f)
and
[tex]1f = 1\frac CV[/tex] ----- 1 farad = 1 capacitance per volt
Resistance (R) [tex]\to[/tex] Ohms [tex]\Omega[/tex]
[tex]1 \Omega = 1\frac{V}{A}[/tex]
The unit of RC is the product of the unit of R by the unit of C.
i.e.
[tex]RC = 1f \times 1\Omega[/tex]
Substitute [tex]1f = 1\frac CV[/tex]
[tex]RC = 1\frac CV \times 1\Omega[/tex]
Substitute [tex]1 \Omega = 1\frac{V}{A}[/tex]
[tex]RC = 1\frac CV \times 1\frac VA[/tex]
Cancel out volts (V)
[tex]RC = 1\frac CA[/tex]
[tex]\frac CA[/tex] means Coulomb per Ampere
Hence, the unit of RC is Coulomb per Ampere.
Read more about units at:
https://brainly.com/question/10167613
the weight of body is less at moon than its weight is more at earth
Answer:
Gravity
Explanation:
There's no gravity on space so you're floating
A vehicle starts from rest with a uniform acceleration of 2m/s2.Find the final velocity of the vehicle after covering a distance of 400m
Answer:
40
Explanation:
vi=0
a=2
vf=?
d=400
vf^2=vi^2+2ad
vf^2=0+2×2×400=1600
vf=√1600=40m/s
01:28:29
What type of relationship occurs when two variables both increase or decrease together?
O an inverse relationship
O a positive relationship
a direct relationship
O an indirect relationship
Answer:
an inverse relationship
A gas at a pressure p is compressed to half it original volume and twice its original temperature. The new pressure is
Answer:
4p
Explanation:
If you halve the volume the pressure will double as they are inversely proportional. If you double the temperature the particles have double the kinetic energy so the pressure will double again.
So:
p×2×2 = 4p
Answer:
P V = n R T
P2 V2 / (P1 V1) = T2 / T1
P2 = (T2 / T1) (V1 / V2) P1 = 2 * 2 = 4
What is matter made of.
Answer:
Matter is made up of atoms
Answer:
Mater is made up of atoms.
Explanation:
Atoms come together to form molecules,which are the building blocks for all types of matter.
Jake launches a water balloon at an angle of 35° above the horizontal. If he sends it flying with an initial velocity of 3 m/s, how far away does Fred (who is the same height as Jake) need to be for it to hit him (assuming Jake has a good aim)?
Answer:
R = 0.86 m
Explanation:
The formula for the range of the projectile motion can be used here:
[tex]R = \frac{v^2 Sin2\theta}{g}[/tex]
where,
R = Range of projectile = distance between Jake and Fred = ?
v = launch speed = 3 m/s
θ = Launch Angle = 35°
g = acceleration due to gravity = 9.81 m/s²
Therefore,
[tex]R = \frac{(3\ m/s)^2Sin[(2)(35^o)]}{9.81\ m/s^2}\\\\[/tex]
R = 0.86 m
9. In a __________ collision, 100% of both vehicles' speed is directed towards the point of impact. A. head-on B. rear-end C. side-impact
Answer: A
Explanation:
:)
What does the sun use for nuclear fusion?
Answer:
The sun uses hydrogen for nuclear fusion.
Answer:
Hydrogen
Explanation:
What is the distance to school if it took bob 1 hour to get to it going at the speed of 1 km/h.
Answer:
1 km
Explanation:
Bob travels at one km/h and it takes him one hour to get there.
10. If the mass of the Earth is... increased by a factor of 2, then the Fgrav is ______________ by a factor of _______. ... increased by a factor of 3, then the Fgrav is ______________ by a factor of _______. ... decreased by a factor of 4, then the Fgrav is ______________ by a factor of _______.
Answer:
If the mass of the Earth is increased by a factor of 2, then the Fgrav is increased by a factor of 2.
If the mass of the earth is increased by a factor of 3, then Fgrav is increased by a factor of 3.
If the mass of the earth is decreased by a factor of 4, then the Fgrav is decreased by a factor of 4
Explanation:
In order to solve this question, we must take into account that the force of gravity is given by the following formula:
[tex]F_{g0}=G \frac{mM_{E0}}{r^{2}}[/tex]
So if the mass of the earth is increased by a factor of 2, this means that:
[tex]M_{Ef}=2M_{E0}[/tex]
so:
[tex]F_{gf}=G \frac{2mM_{E0}}{r^{2}}[/tex]
Therefore:
[tex]\frac{F_{gf}}{F_{g0}}=\frac{G \frac{2mM_{E0}}{r^{2}}}{G \frac{mM_{E0}}{r^{2}}}[/tex]
When simplifying we end up with:
[tex]\frac{F_{gf}}{F_{g0}}=2[/tex]
so if the mass of the Earth is increased by a factor of 2, then the Fgrav is increased by a factor of 2.
If the mass of the earth is increased by a factor of 3
So if the mass of the earth is increased by a factor of 2, this means that:
[tex]M_{Ef}=3M_{E0}[/tex]
so:
[tex]F_{gf}=G \frac{3mM_{E0}}{r^{2}}[/tex]
Therefore:
[tex]\frac{F_{gf}}{F_{g0}}=\frac{G \frac{3mM_{E0}}{r^{2}}}{G \frac{mM_{E0}}{r^{2}}}[/tex]
When simplifying we end up with:
[tex]\frac{F_{gf}}{F_{g0}}=3[/tex]
so if the mass of the Earth is increased by a factor of 3, then the Fgrav is increased by a factor of 3.
If the mass of the earth is decreased by a factor of 4
So if the mass of the earth is decreased by a factor of 4, this means that:
[tex]M_{Ef}=\frac{M_{E0}}{4}[/tex]
so:
[tex]F_{gf}=G \frac{mM_{E0}}{4r^{2}}[/tex]
Therefore:
[tex]\frac{F_{gf}}{F_{g0}}=\frac{G \frac{mM_{E0}}{4r^{2}}}{G \frac{mM_{E0}}{r^{2}}}[/tex]
When simplifying we end up with:
[tex]\frac{F_{gf}}{F_{g0}}=\frac{1}{4}[/tex]
so if the mass of the Earth is decreased by a factor of 4, then the Fgrav is decreased by a factor of 4.
A spring attached to a mass is at rest in the initial position (not shown). The spring is compressed in position A and is then released, as shown in position B. Which equation describes conservation of energy in position A?
Answer:
Explanation:
When the spring is compressed, it is compressed to its amplitude (whereas equilibrium is the spring's natural length with no mass attached to it and displacement is the spring's reaction to a mass hung on the end of it without any "extra" pushing or pulling on the mass). It is at the amplitude where the spring experineces max potential energy, which is choice 2, E = mph
Answer:
its c
Explanation:
...
You are accelerating upwards in an elevator when the net force on you increases. What happens to the acceleration
Answer:
the acceleration of the elevator is increasing
Explanation:
For this exercise we propose the solution using Newton's second law
F -W = m a
F = m (g + a)
If the net force increases, it implies that the acceleration of the elevator is increasing, since the acceleration of gravity is constant as the ascent is accelerating.
how long the period of the earth's circulation (365 1/4) in seconds?
Answer:
31,556,736 seconds
Explanation:
The period of Earth's orbit around the Sun, T = (365 + 1/4) days (three hundred and sixty five and a quarter days
The period of Earth's orbit around the Sun in seconds is given by converting, T = [tex]365\frac{1}{4} \, days[/tex] into seconds as follows;
There are 60 seconds per minute, 60 minutes in each hour, 24 hours within each day, therefore, we get;
T = [tex]365\frac{1}{4}[/tex]×60 sec/min × 60 min/hr. × 24hr/day = 31,556,736 seconds
help me daddyz Alice did an experiment to find the relationship between the angle at which a ray of light strikes a mirror and the angle at which the mirror reflects the light. She placed a ray box in front of a mirror. She changed the angle at which the light from the ray box struck the mirror and noted the corresponding angle at which the mirror reflected the light. Which of the following is the control variable in this experiment? The ray box used as the source of light The direction along which the light moves Angle at which the light from the ray box strikes the mirror Angle at which the mirror reflects the light from the ray box
Answer:
The ray box used as the source of light
Answer: its A
Explanation: i just did the test and got it right also known. The ray used as the source of light
If displacement has a magnitude AND direction is it a scalar or vector quantity?
scalar
vector
Explanation:
Obviously vector quantity
what is acceleration
[tex]\boxed{\large{\bold{\blue{ANSWER~:) }}}}[/tex]
[tex]\sf What \: is \: acceleration? \\ \\ \sf The \: rate \: of \: change \: of \: velocity \: of \: an \\ \sf object \: with \: respect \: to \: time \\ \sf is \: known \: as \: acceleration. [/tex]
The Sun's energy comes from which nuclear reaction?
Answer:
the sun energy comes from nuclea fution
A boy is moving a stone in a horizontal circle by mean of a thread attached to ut. The length if the threads us 1 m and the weight of the stone is 0.02 kg . The maximum tension of the thread can withstand us 1 ×10 ^-4 N. The boy is gradually increasing the speed if rotation. At what speed if the stone does the thread break ?
Answer:
Explanation:
This is a centripetal force problem where tension supplies the centripetal force needed to keep the stone moving in a circular manner. That formula for that is
[tex]F_c=T=\frac{mv^2}{r}[/tex] and filling in what we know:
[tex]1*10^{-4}=\frac{.02v^2}{1}[/tex] and solve that for v:
[tex]v=\sqrt{\frac{1*10^{-4}}{.02} }[/tex] which gives us a velocity of .07 m/s. Anything greater than this will break the string.
Having the correct posture and the degree or severity of braking, acceleration and steering inputs have a direct result on the ability of a motorist to effectively address changes in __________?
Answer: Vehicle Balance
Explanation:
Vehicle balance simply means how the weight of a vehicle is distributed across its tires which connects to the road
It should be noted that there'll be a shift in the balance of a vehicle when the braking, acceleration, or turning bring about a scenario in which the weight of th vehicle moves from one area to another.
if the volume of cylinder is 1000 cm with 14cm height. Then find the radius of cylinder
Answer:
radius=4.77cm
Explanation:
given
r=? ,h=14 , v=1000
then using the formula
[tex]r = \sqrt{ \frac{v}{\pi \: h} } [/tex]
= √1000/π•14
=4.77cm
6. traction a. friction between a tire and the road.b. pushes a moving object out of a curve and into a straight linec. the ability of a car to hold a straight lined. a road higher in the center than on either edge 7. kinetic energy a.a force that keeps objects moving in a straightb. reduces the effects of inertiac. energy of motiond. a road higher in the center than on either edge 8. force of impact a. a force that keeps objects moving in a straight line.b. a road higher in the center than on either edgec. the force with which a moving vehicle hits another objectd. perception distance, reaction distance, and braking distance
Answer:
6. a. friction between a tire and the road
7. c. energy of motion
8. c. the force with which a moving vehicle hits another object
Explanation:
6. As a car moves along the road, the tires push back against the ground. As tires push back against the ground, the road exerts and opposing force to the motion of the tires. This opposing force is the friction between the tires and the road. This opposing force between the tires and the rad is called traction.
So, the answer is a
7. As an object moves, it has energy. This energy due to its motion is called kinetic energy.
So, the answer is c
8. When a moving vehicle hits another object, it exerts a force on the object. The process of the vehicle hitting the other object is called impact and the force exerted on the object is called the force of impact.
So, the answer is c.
A thin rod of length 1.4 m and mass 180 g is suspended freely from one end. It is pulled to one side and then allowed to swing like a pendulum, passing through its lowest position with angular speed 1.80 rad/s. Neglecting friction and air resistance, find (a) the rod's kinetic energy at its lowest position and (b) how far above that position the center of mass rises.
Answer:
[tex]K.E = 0.1905 J[/tex]
Explanation:
From the question we are told that:
Length [tex]L=1.4m[/tex]
Mass [tex]m=180g[/tex]
Angular Velocity [tex]\omega=1.80rads/s[/tex]
Generally the equation for Kinetic energy K.E is mathematically given by
[tex]K.E =0.5 (1/3 ML^2 )w^2[/tex]
[tex]K.E =0.5 ( 1/3 * 0.18 * 1.4^2 ) 1.8^2[/tex]
[tex]K.E = 0.1905 J[/tex]
A neutral object must have _______________ A. An equal amount of positive and negative charges B. no charges present at all C. more positive than negative charges D. more negative than positive
Answer:
A
Explanation:
Consider a question you may not have considered before. Suppose you have a mole of sodium in a container that contains nothing that it will react with. A mole of anything is 6.02 * 10^23 (in this case atoms).
Suppose that every one of those atoms has contributed 1 electron to something.
Do you think it would be safe to touch the container knowing that there are 6.02 * 10^23 positive charges all eager to get another electron, because they don't like repelling each other.
Safe or not? I'll give you a hint. A lightning bolt does not contain anywhere near 6.02*10^23 charges. No where near.
So -- since you never get a shock from just touching anything, There must not be electrons or ions present.
The answer is A
HOW OLD IS THE ISS? HOW LONG HAS IT BEEN OPERATIONAL?
Answer:
bhai nam kya hai (whats your name)
Explanation:
please comment
Find the transformation matrix that rotates a rectangular coordinate system through an angle of 60 about axes equal angels with original three coordinate axes
Answer:
[tex]M = \left[\begin{array}{ccc}cos \ 60&0\\0&-sin \ 60\end{array}\right][/tex]
Explanation:
To find the matrix, let's decompose the vectors, the rotated angle is (-60C) for the prime system
x ’= x cos (-60)
y ’= y sin (-60)
we use
cos 60 = cos (-60)
sin 60 = - sin (-60)
we substitute
x ’= x cos 60
y ’= - y sin 60
the transformation system is
[tex]\left[\begin{array}{ccc}x'\\y'\end{array}\right] = \left[\begin{array}{ccc}cos 60&0\\0&-sin60\end{array}\right] \ \left[\begin{array}{ccc}x\\y\end{array}\right][/tex]x '
the transformation matrix is
[tex]M = \left[\begin{array}{ccc}cos \ 60&0\\0&-sin \ 60\end{array}\right][/tex]
4. Thousands of which solar system bodies orbit the sun between Mars and Jupiter?
Asteroids
Comets
Meteorites
Meteors
help
Answer:
asteroids
Explanation:
There is an asteroid belt between Mars and Jupiter
You can see stars brighter than magnitude +6 with your naked eye under dark sky conditions, and you can also see the full moon at magnitude –13. (You can glance at the Sun, which is at magnitude –27, but you can't safely look at the Sun.) Given these limits, what is the dynamic range of the naked eye?
A box of tools rests in the back of a pickup truck. The truck accelerates to the north and the box remains at rest in the truck. The direction of the friction force on the box of tools is _____.
Answer:
The direction of friction force is toards north.
Explanation:
A tool box is at rest on the back of a track. The truck is accelerating towards north.
As the frame of reference is acceleratinf so it is a non inertial frame of reference.
Thus, teh toolkit experineces a pseudo force towards the south direction.
According to the question, the toolbox is at rest so the fiction force is balances by teh psheudoforce, and thus teh friction force is acting toards north.
