Answer:
Cold Front. A side view of a cold front (A, top) and how it is represented on a weather map (B, bottom).
Warm Front. ...
Stationary Front. ...
Occluded Front.
Answer:
Front 3 is an occluded front. A cold air mass moves toward warmer air. The colder, heavier air pushes the warm air upward until it’s wedged between two cold air masses. Clouds can form from the lifting of the warm air.
Explanation:PLATO
Are women sports underpaid compared with man? (Example: Women's USA soccer team is paid way less then Men's USA soccer team)
DO NOT PUT LINKS!!
Answer:
Yeah of course
Explanation:
Its obvious because more people are attracted to men soccer
Which two types of energy are being produced in the picture?
A
electrical energy and light energy
B
electrical energy and sound energy
C
mechanical energy and light energy
D
mechanical energy and sound energy
Answer:
dion sanders
Explanation:c
3. A warehouse employee is pushing a 30.0 kg desk across a floor at a
constant speed of 0.50 m/s. How much work must the employee do on
the desk to change the speed to 1.00 m/s?
Answer: The employee must do 11.2308 Joules of work
Explanation:
Work done = force × distance
But
Force = ma(mass x acceleration due to gravity)
F = 30×9.8
F = 294N
Also distance moved can be found using the equation
v² = u² +2gS
1.00 ² = 0.50²+2(9.8)S
1 =0.25+19.6S
1-0.25 =19.6S
0.75=19.6S
S=0.75/19.6
S = 0.0382m
Work done = force × distance = FS
Work done = 294 N X 0.0382m
Workdone =11.2308Nm = 11.2308 Joules
Work done required by the employee to do on the desk to change the speed to 1.00 m/s is 11.3 J.
What is work done?Work done is the force applied on a body to move it over a distance. Work done by a body can be given as,
[tex]W=Fd[/tex]
Here (F) is the magnitude of force and (d) is the distance traveled.
From the second law of motion, the force is product of mass time acceleration. Thus the above formula can be given as,
[tex]W=(ma)d[/tex]
For the gravitational acceleration, it can be written as,
[tex]W=(mg)d\\W=mgd[/tex]
The constant speed by which, the warehouse employee is pushing the desk across a floor is 0.50 m/s and the the final speed of the desk is 1 m/s.
Thus, the distance traveled by it can be find out using the third law of motion as,
[tex]v^2-u^2=2gd\\1^2-0.25^2=2\times9.8\times d\\d=0.0382\rm m[/tex]
As the mass of the desk is 30 kg and the distance moved is 0.382 meters. Thus, put the values in the above formula as,
[tex]W=30\times9.81\times0.0382\\W\cong11.3\rm J[/tex]
Thus the work done required by the employee to do on the desk to change the speed to 1.00 m/s is 11.3 J.
Learn more about the work done here;
https://brainly.com/question/25573309
using a diagram explain how acceleration can be obtained from a velocity time graph
Answer:
For any v-t graph the acceleration is the slope of the graph. For average acceleration in a time period ‘t’ consider the change in velocity in time t and divide it by the time t. For instantaneous acceleration you need to go into the realm of differential calculus.
Explanation:
I hope this helps! I would really appreciate it if you would please mark me brainliest! Have a blessed day!
The bones of the middle ear cause which structure in the inner ear to vibrate and change the sound into signals?
a) eardrum
b) cochlea
c) hammer
d) auricle
Answer:
B
Explanation:
The cochlea is the part of the inner ear involved in hearing. It is a spiral-shaped cavity in the bony labyrinth, in humans making 2.75 turns around its axis, the modiolus.
Answer:
the answer is the cochlea
Explanation:
the eardrum receives the sounds and the cochlea "decifers them" so you know what words people are saying or what sound is playing.
A. Dashed Line
B. Solid Line
Which law best describes contact force
A.
second law
B.
third law
C.
law of gravity
D.
first law
Answer: the third law
Explanation:
An unbalanced force is at work when
A.
a book sits on a shelf.
B.
a piece of paper is on the floor.
C.
a model rocket takes off.
D.
a glass sits on a table.
What is the difference in average speed between two car, one that traveled 150 kilometers in 5 hours and the other that traveled 130 kilometers in the same time?
Answer:
just like he saide you can downloude the answer
A 5kg book is slid across the floor with an initial velocity of 3m/s. It slows and stops due to the friction with the floor. How man joules of work did friction do?
Answer:
SUP DAD i love cookies
Explanation:
yuh
Would the following reaction be endothermic or exothermic? Why?
CH4 + 02 --> CO2 + H2O + Energy
A. Exothermic because energy is a reactant
B. Endothermic because energy is a reactant
C. Endothermic because energy is a product
D. Exothermic because energy is a product
Answer:
D. Exothermic because energy is a product
Explanation:
ENDOTHERMIC REACTION: A chemical reaction is considered endothermic if the energy is absorbed during the reaction. In other words, if the energy is required by the reactants to proceed with the reaction, then the reaction is endothermic.
EXOTHERMIC REACTION: A chemical reaction is considered exothermic if the energy is released during the reaction. In other words, if the energy is produced as a product of the reaction, then the reaction is exothermic.
Hence, the correct answer for this question will be:
D. Exothermic because energy is a product
how to find a cow
write a 4-5 sentence answer
Answer:
Go out into the country. Look on a farm. Look in a barn. Listen for, "MOOOOO." You found a cow.
Explanation:
What is the force required to accelerate an object with a mass of 5 kg and an acceleration of
2 m/s22
No Links!!!!!!!!!!!!!!!!!!!!!!!!!! Can you guys help me with this? Please :)
Answer:
C and True :)
Explanation:
Hope you got it right!
a student preformed a trick using a bar magnet and a paper clip. The paper clip was attached to a piece of string that was taped to the table. The clip appears to float just below the magnet. Explain how the floating paper clip trick works.
Un acróbata de masa M, se impulsa hacia arriba con una velocidad v0 desde un
trampolín. Mientras sube, a una altura h sobre el trampolín, recoge a un mono entrenado de masa m. ¿Cuál es la altura máxima que alcanzan el mono y el acróbata?
Answer:
La altura máxima que alcanzan el mono y el acróbata es [tex]z = \frac{1}{2}\cdot \left(\frac{M}{M+m} \right)\cdot v_{o}^{2}+\left(1-\frac{M\cdot g}{M+m} \right)\cdot h[/tex].
Explanation:
Asumamos que tanto el acróbata, el mono y el sistema acróbata-mono son conservativos y que el acróbata comienza su acción a una altura de cero. El estudio se divide en dos etapas: (i) El acróbata se dirige al mono, (ii) El acróbata recoge al mono y alcanzan una altura máxima.
Para resolver esta cuestión, nos valemos del Principio de Conservación de la Energía.
Parte I
La energía cinética traslacional inicial ([tex]K_{1,a}[/tex]) es igual a la suma de la energía cinética traslacional final ([tex]K_{2, a}[/tex]) y la energía potencial gravitacional final ([tex]U_{g,2,a}[/tex]).
[tex]K_{1,a} = K_{2,a} + U_{g,2,a}[/tex] (1)
[tex]\frac{1}{2}\cdot M \cdot v_{o}^{2} = \frac{1}{2}\cdot M\cdot v_{1}^{2} + M\cdot g \cdot h[/tex] (1b)
Donde:
[tex]M[/tex] - Masa del acróbata.
[tex]g[/tex] - Constante gravitacional.
[tex]v_{o}[/tex] - Rapidez inicial del acróbata.
[tex]v_{1}[/tex] - Rapidez del acróbata justo antes de recoger al mono.
[tex]h[/tex] - Altura inicial del mono.
Parte II
La suma de las energías iniciales cinética traslacional ([tex]K_{2, a}[/tex]) y potencial gravitacional de acróbata ([tex]U_{g,2,a}[/tex]) y la energía inicial potencial gravitacional del mono ([tex]U_{g,2,m}[/tex]) es igual a la suma de las energías potenciales gravitacionales iniciales del sistema acróbata-mono ([tex]U_{g,3,a+m}[/tex]), es decir:
[tex]K_{2,a} + U_{g,2,a}+U_{g,2,m} = U_{g,3,a+m}[/tex] (2)
[tex]\frac{1}{2}\cdot M\cdot v_{1}^{2} + (M+m)\cdot g \cdot h = (M+m)\cdot g \cdot z[/tex] (2b)
Donde:
[tex]m[/tex] - Masa del mono.
[tex]z[/tex] - Altura máxima del sistema acróbata-mono.
De (1b) tenemos que la rapidez del acróbata justo antes de recoger al mono es:
[tex]\frac{1}{2}\cdot M \cdot v_{o}^{2} = \frac{1}{2}\cdot M\cdot v_{1}^{2} + M\cdot g \cdot h[/tex]
[tex]v_{o}^{2} = v_{1}^{2}+2\cdot g\cdot h[/tex]
[tex]v_{1} = \sqrt{v_{o}^{2}-2\cdot g\cdot h}[/tex]
Finalmente, la altura máxima alcanzada por el sistema acróbata-mono es:
[tex]\frac{1}{2}\cdot M\cdot v_{1}^{2} + (M+m)\cdot g \cdot h = (M+m)\cdot g \cdot z[/tex]
[tex]z = \frac{M\cdot v_{1}^{2}}{2\cdot (M+m)\cdot g}+h[/tex]
[tex]z = \frac{1}{2}\cdot \left(\frac{M}{M+m} \right)\cdot (v_{o}^{2}-2\cdot g\cdot h)+ h[/tex]
[tex]z = \frac{1}{2}\cdot \left(\frac{M}{M+m} \right)\cdot v_{o}^{2}+\left(1-\frac{M\cdot g}{M+m} \right)\cdot h[/tex]
La altura máxima que alcanzan el mono y el acróbata es [tex]z = \frac{1}{2}\cdot \left(\frac{M}{M+m} \right)\cdot v_{o}^{2}+\left(1-\frac{M\cdot g}{M+m} \right)\cdot h[/tex].
a
400 12
M
b
290 12
с
The question below refers to the circuit shown in the image
--
12.0 y
If the voltage across the 400 resistor is 7 V, what is the voltage across the 290 Q resistor?
O 5V
O 7V
O 9V
O 12 V
1
2
3
4
5
Answer:
i would think c
Explanation:
HELP THIS IS TIMED PLEASE OMG
Answer:
d) 40000 kgm/s
Explanation:
The formula for momentum is p = m*v
so p = 100*400
p = 40000 kgm/s
1200 calories isfind the change in internal energy of the system 1200 calories is removed from a gas held at constant volume give answers in kilojoule
6
Which of these statements is true?
А
Acceleration in the direction of motion slows you down
B.
Acceleration in the direction of motion speeds you up
C
Acceleration against the direction of motion has no effect
on your speed
D
Acceleration against the direction of motion speeds you up
Answer:
B. Acceleration in the direction of motion speeds you up
Explanation:
Acceleration is defined as when something gains speed. For example, when a car speeds up. Deceleration is when the car slows down, and looses speed. When defining these terms, think of a car going faster, then slowing down at a red light.
What is the average speed of a car that travelled 400 miles in 6 hours?
Answer:
About 66 miles per hour
Explanation:
Based on the information given we can assume the car traveled the same number of miles every hour meaning all we need to do is divide.
400/6 ≈ 66 miles per hour
Answer
66 mph
Explanation:
400 ÷ 6 = 66.666666666666666.......
Alex swims at an average speed of 4.5 m/s how far does he swim in one minute 24 seconds
Answer:
378
Explanation:
60 seconds in one minute
add the 24 seconds
multiply it by 4.5
60 + 24 = 84
4.5 x 84 = 378
Answer:D 125
Explanation:
a simple mobile is made by attaching 4 small balls(0.1 kg each)
When the Asthenosphere transfers heat, what happens?
Convection Currents, Earthquakes, volcanic eruptions, or weathering?
What are two ways fusion is used in the real world.
Answer:
The main application for fusion is in making electricity. Most fusion reactors make less radiation than the natural background radiation we live with in our daily lives. ... Clean - No combustion occurs in nuclear power (fission or fusion), so there is no air pollution.
how does the input distance of a third-class lever compare to the output distance
Answer:
A first-class lever: fulcrum is between input and output force; second-class lever: output force is between input force and fulcrum; third-class lever: input force is between fulcrum and output force
Which of the following explanations is correct about the wave that travels through the medium?
A. The vibration that produced the wave must have been perpendicular to the direction of motion of the resulting wave, because the figure shows that the resulting wave is a longitudinal wave.
B. The vibration that produced the wave must have been perpendicular to the direction of motion of the resulting wave, because the figure shows that the resulting wave is a transverse wave.
C. The vibration that produced the wave must have been parallel to the direction of motion of the resulting wave, because the figure shows that the resulting wave is a longitudinal wave.
D. The vibration that produced the wave must have been parallel to the direction of motion of the resulting wave, because the figure shows that the resulting wave is a transverse wave.
If this decay has half-life of 2 years, how many years would it take for 10.8 g Protactinium-231 to remain given an initial mass of 86.3 g?
Answer:
Time = 6 years
Explanation:
First, we will calculate the no. of half life periods required to reduce the mass of Protactinium to the given value:
[tex]m' = \frac{m}{2^{n} } \\\\2^n = \frac{m}{m'}[/tex]
where,
n = no. of half-life periods = ?
m = initial mass = 86.3 g
m' = remaining mass = 10.8 g
Therefore,
[tex]2^n = \frac{86.3\ g}{10.8\ g}\\\\2^n = 8\\2^n = 2^3[/tex]
Since the bases are the same. Therefore equating powers:
n = 3
Now we calculate the time:
[tex]Time = (n)(Half-Life)\\Time =(3)(2\ years)[/tex]
Time = 6 years
When light hits a second transparent medium, light-
A. Reflects and Refracts
B. Refracts only
C. Reflects only
Answer:
C. Reflects only
Objects A and B are brought close to each other. Object A will soon become positively charged. Identify the charge that must transfer for
this
situation to occur.
