The valid call to the function installApplication is

void main(  )
{
 // call the function installApplication
}

void installApplication(char appInitial, int appVersion)
{
  // rest of function not important
}
Select one:

A.
int x =installApplication(‘A’, 1);

B.
installApplication(‘A’, 1);

C.
int x= installApplication(  );

D.
installApplication(2 , 1);

Answer:

Explanation:

Marketing your product directly over the internet can lead to much greater profits and there are many options that you can choose from in order to target the correct audience. Unfortunately, doing so does require marketing knowledge and is basically like growing a business. If you were to use intermediaries they already have the knowledge necessary to market your product but will take a percentage of the profits, which will ultimately limit your gains. Since Gray London is a race car driver, I am assumming that he does not have any prior technological expertise or marketing expertise, therefore I would recommend using intermediaries.

Answer:

Job order production

Explanation:

A job order production has the least flexibility and is best suited for mass production.

It also has an arrangement of machines that process identical products in a predefined order, with automatic movement of materials between machines.

brainleist please..

Answer -------> Transfer line <---------

please click on the picture look at the PICTURE for the correct answer.

Explanation:

jwjajahabauiqjqjwjajjwwjnwaj

Answer:

[tex](a)\ 14"."43[/tex]

[tex](b)\ 0"0"7[/tex]

[tex](c)\ 2"8 - 2"611[/tex]

[tex](d)\ 7"(1 + 1)"46[/tex]

[tex](e)\ "1"23"4"30"7"17[/tex]

Explanation:

Required

Evaluate each expression

The simple rules to follow are:

(1) All expressions in bracket will be evaluated based on its data type

(2) Divisions will return only integer values

(3) Integers immediately after string values will be concatenated (not added)

So, the results are as follows:

[tex](a)\ 4 + 1 + 9 + "." + (-3 + 10) + 11 / 3[/tex]

Evaluate till a string is encountered

[tex]4 + 1 + 9 = 14[/tex]

Followed by "."

Then:

[tex](-3 + 10) = 7[/tex]

[tex]11/ 3 = 3[/tex]

[tex]"." + (-3 + 10) + 11/3 = "."73[/tex] -- because expressions after string operations are concatenated.

So, we have:

[tex]4 + 1 + 9 + "." + (-3 + 10) + 11 / 3 = 14"."43[/tex]

[tex](b)\ 8 + 6 * -2 + 4 + "0" + (2 + 5)[/tex]

Evaluate till a string is encountered

[tex]8 + 6 * -2 + 4 =0[/tex]

[tex]"0" + (2 + 5) ="0"7[/tex]

So, we have:

[tex]8 + 6 * -2 + 4 + "0" + (2 + 5) = 0"0"7[/tex]

[tex](c)\ 1 + 1 + "8 - 2" + (8 - 2) + 1 + 1[/tex]

Evaluate till a string is encountered

[tex]1 + 1 = 2[/tex]

[tex]"8 - 2" + (8 - 2) + 1 + 1 = "8 - 2"611[/tex]

So, we have:

[tex]1 + 1 + "8 - 2" + (8 - 2) + 1 + 1 = 2"8 - 2"611[/tex]

[tex](d)\ 5 + 2 + "(1 + 1)" + 4 + 2 * 3[/tex]

Evaluate till a string is encountered

[tex]5 + 2 =7[/tex]

[tex]"(1 + 1)" + 4 + 2 * 3 = "(1 + 1)"46[/tex] --- multiply 2 and 3, then concatenate

So, we have:

[tex]5 + 2 + "(1 + 1)" + 4 + 2 * 3= 7"(1 + 1)"46[/tex]

[tex](e)\ "1" + 2 + 3 + "4" + 5 * 6 + "7" + (8 + 9)[/tex]

Since a string starts the expression, the whole expression will be concatenated except the multiplication and the expressions in bracket.

So, we have:

[tex]"1" + 2 + 3 + "4" + 5 * 6 + "7" + (8 + 9) = "1"23"4"30"7"17[/tex]

Answer:

give me number I will explain fast I am free now reply bro I am waiting

Answer:

To put it into simple words: the future of marketing automation is customers centric.  

From data collection to lead generation, marketing automation will stay B2B marketers’ favorite in the future.  Based on the current analytics, let’s have a look at how automation is driving lead generation today as well as what’s to come.

Marketing automation is a dynamic field and it will continue to evolve and transform processes in the future. If you in the marketing frontier, and looking to transform your lead generation processes, don’t be afraid to give marketing automation a shot.

Answer:

it is....insert tab..B

Explanation:

insert tab includes editing options

Answer:

Authorization

Explanation:

The kind of service that they are requesting is known as Authorization. This is basically when a user, such as the DevOps team in this scenario, is requesting permission to access a certain service or function that is locked. In this scenario, the services being requested are the read/write access which would allow the DevOps team to manipulate the data in the storage bucket. This is usually locked because the data is sensitive and innapropriate changes can cause many errors in the system. Therefore, authorization is needed to make sure that only specific users have access.

Answer:

C. log

Explanation:

The log is a sequence of log records, recording all the update activities in the database

hope this helps

Answer:

C. Log is the

answer

Explanation:

a sequence of log records recording all update activity in database

Answer:

Multiple devices can be connected

The social network created through digital technology is referred to as a "digital network." It provides phone, video, data, and other network services for digital switching and transmission.

In order to align the network with business demands, it has markets, data networks, and communications networks.

Digital networks' core are networking components like switches, routers, and access points. These tools are used to link networks to other networks, secure equipment like computers and servers connected to organizational networks, and analyze data being sent across networks.

Through cloud-enabled central administration, digital networks provide end-to-end network services for on-premises and cloud space. All network components are monitored, analyzed, and managed by a central server.

Therefore, The social network created through digital technology is referred to as a "digital network." It provides phone, video, data, and other network services for digital switching and transmission.

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Answer:

The id selector selects a particular html element

Explanation:

The id selector is uses the id attribute to select a specific html element. For example, if we have a particular header which is an html element and we want to give it a particular background color, we use the id selector and give it an id attribute in the CSS file. An example of an html header with id = 'blue' is shown below. The style sheet is an internal style sheet.

!doctype html

<html>

<head>

<title>Test</title>

<style>

#blue { background-color: blue;

}

</style>

</head>

<body>

<h1 id = 'blue'>Our holiday</h1>

<p>This is the weekend</p>

</body>

</html>

Answer:

Explanation:

ICT is a device that display and command information outside.

Answer:

"if" is the right response.

Explanation:

Answer:

Code:-

// Program takes a hot dog order

// And determines price  

using System;

using static System.Console;  

class DebugFour1

{

   static void Main()

   {

       const double BASIC_DOG_PRICE = 2.00;

       const double CHILI_PRICE = 0.69;

       const double CHEESE_PRICE = 0.49;

       String wantChili, wantCheese;

       double price;

       Write("Do you want chili on your dog? ");

       wantChili = ReadLine();

       Write("Do you want cheese on your dog? ");

       wantCheese = ReadLine();

       if (wantChili == "Y")

       {

           if (wantCheese == "Y")

               price = BASIC_DOG_PRICE + CHILI_PRICE + CHEESE_PRICE;

           else

               price = BASIC_DOG_PRICE + CHILI_PRICE;

       }

       else

       {

           if (wantCheese == "Y")

               price = BASIC_DOG_PRICE + CHEESE_PRICE;

           else

               price = BASIC_DOG_PRICE;

       }

       WriteLine("Your total is {0}", price.ToString("C"));

   }

}

Base to be converted to was not included but we would assume conversion to base 10(decimal)

Answer and Explanation:

The 3DF in base 16 is a hex number so we need to convert to its equivalent binary/base 2 form:

We therefore each digit of given hex number 3DF in base 16 to equivalent binary, 4 digits each.

3 = 0011

D = 1101

F = 1111

We then arrange the binary numbers in order

3DF base 16 = 1111011111 in base 2

We then convert to base 10 =

= 1x2^9+1x2^8+1x2^7+1x2^6+0x2^5+1x2^4+1x2^3+1x2^2+1×2^1+1×2^0

= 991 in base 10

Answer:

are better data entry designs than entering data directly to a table. ... hence a user can design input fields linked to several tables/queries.

Explanation:

Input screens are better data entry designs than entering data directly to a table because a user can design input fields linked to several tables/queries.

Digital information generally consists of data that is created or prepared for electronic systems and devices such as computers, screens, calculators, communication devices. These information are stored by cloud.

They are converted from digital to analog and vice versa with the help of a device.

Data entered in the table directly is easier than data entry method.

Thus, input screens are better data entry than entering data directly to a table.

Learn more about digital information.

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Answer:

hi..,.................................................

Answer:

supercomputers are the computer that is used in scientific research.

Answer:

super computer is the right answer

Answer:

removeDuplicates() function:-

//removeDuplicates() function removes duplicate elements form linked list.

   void removeDuplicates() {

       //declare 3 ListNode pointers ptr1,ptr2 and duplicate.

       //initially, all points to null.

       ListNode ptr1 = null, ptr2 = null, duplicate = null;

       //make ptr1 equals to head.

       ptr1 = head;

        //run while loop till ptr1 points to second last node.

       //pick elements one by one..

       while (ptr1 != null && ptr1.next != null)

       {

               // make ptr2 equals to ptr1.

               //or make ptr2 points to same node as ptr1.

           ptr2 = ptr1;

           //run second while loop to compare all elements with above selected element(ptr1->val).

           while (ptr2.next != null)

           {

              //if element pointed by ptr1 is same as element pointed by ptr2.next.

               //Then, we have found duplicate element.

               //Now , we have to remove this duplicate element.

               if (ptr1.val == ptr2.next.val)

               {

                  //make duplicate pointer points to node where ptr2.next points(duplicate node).

                       duplicate = ptr2.next;

                       //change links to remove duplicate node from linked list.

                       //make ptr2.next points to duplicate.next.

                   ptr2.next = duplicate.next;

               }

             //if element pointed by ptr1 is different from element pointed by ptr2.next.

               //then it is not duplicate element.

               //So, move ptr2 = ptr2.next.

               else

               {

                   ptr2 = ptr2.next;

               }

           }

           //move ptr1 = ptr1.next, after check duplicate elements for first node.

           //Now, we check duplicacy for second node and so on.

           //so, move ptr1  by one node.

           ptr1 = ptr1.next;

       }

   }

Explanation:

Complete Code:-

//Create Linked List Class.

class LinkedList {

       //Create head pointer.

       static ListNode head;

       //define structure of ListNode.

       //it has int val(data) and pointer to ListNode i.e, next.

   static class ListNode {

       int val;

       ListNode next;

       //constructor to  create and initialize a node.

       ListNode(int d) {

               val = d;

           next = null;

       }

   }

//removeDuplicates() function removes duplicate elements form linked list.

   void removeDuplicates() {

       //declare 3 ListNode pointers ptr1,ptr2 and duplicate.

       //initially, all points to null.

       ListNode ptr1 = null, ptr2 = null, duplicate = null;

       //make ptr1 equals to head.

       ptr1 = head;

       //run while loop till ptr1 points to second last node.

       //pick elements one by one..

       while (ptr1 != null && ptr1.next != null)

       {

               // make ptr2 equals to ptr1.

               //or make ptr2 points to same node as ptr1.

           ptr2 = ptr1;

           //run second while loop to compare all elements with above selected element(ptr1->val).

           while (ptr2.next != null)

           {

              //if element pointed by ptr1 is same as element pointed by ptr2.next.

               //Then, we have found duplicate element.

               //Now , we have to remove this duplicate element.

               if (ptr1.val == ptr2.next.val)

               {

                  //make duplicate pointer points to node where ptr2.next points(duplicate node).

                       duplicate = ptr2.next;

                       //change links to remove duplicate node from linked list.

                       //make ptr2.next points to duplicate.next.

                   ptr2.next = duplicate.next;

               }

             //if element pointed by ptr1 is different from element pointed by ptr2.next.

               //then it is not duplicate element.

               //So, move ptr2 = ptr2.next.

               else

               {

                   ptr2 = ptr2.next;

               }

           }

           //move ptr1 = ptr1.next, after check duplicate elements for first node.

           //Now, we check duplicacy for second node and so on.

           //so, move ptr1  by one node.

           ptr1 = ptr1.next;

       }

   }

   //display() function prints linked list.

   void display(ListNode node)

   {

       //run while loop till last node.

       while (node != null)

       {

               //print node value of current node.

           System.out.print(node.val + " ");

           //move node pointer by one node.

           node = node.next;

       }

   }

   public static void main(String[] args) {

       //Create object of Linked List class.

       LinkedList list = new LinkedList();

       //first we create nodes and connect them to form a linked list.

       //Create Linked List 1-> 2-> 3-> 2-> 4-> 2-> 5-> 2.

       //Create a Node having node data = 1 and assign head pointer to it.

       //As head is listNode of static type. so, we call head pointer using class Name instead of object name.

       LinkedList.head = new ListNode(1);

       //Create a Node having node data = 2 and assign head.next to it.

       LinkedList.head.next = new ListNode(2);

       LinkedList.head.next.next = new ListNode(3);

       LinkedList.head.next.next.next = new ListNode(2);

       LinkedList.head.next.next.next.next = new ListNode(4);

       LinkedList.head.next.next.next.next.next = new ListNode(2);

       LinkedList.head.next.next.next.next.next.next = new ListNode(5);

       LinkedList.head.next.next.next.next.next.next.next = new ListNode(2);

       //display linked list before Removing duplicates.

       System.out.println("Linked List before removing duplicates : ");

       list.display(head);

       //call removeDuplicates() function to remove duplicates from linked list.

       list.removeDuplicates();

       System.out.println("")

       //display linked list after Removing duplicates.

       System.out.println("Linked List after removing duplicates :  ");

       list.display(head);

   }

}

Output:-

Answer:

twitt

Explanation:

The correct answer to this open question is the following.

Unfortunately, you did not provide any context or background about the situation of Sally and the problem with her slides. We do not know it, just you.

However, trying to be of help, we can comment on the following general terms.

When someone does not meet professional expectations, this means that this individual did not prepare her presentation, lacked technical skills, did not included proper sources, or missed the proper visual aids to make the presentation more attractive and dynamic.

What Sally can improve about her slides is the following.

She can design a better structure for the presentation to have more congruence.

Sally has to clearly establish the goal or goals for her presentation.

She has to add many visuals instead of plain text. This way she can better capture the interest of her audience.

If she can use more vivid colors instead of pale or dark ones, that would be best.

No paragraphs unless necessary. She better uses bullet points.

Take care of the tone of her voice. During her practice, she can record her vice to check how it sounds.

Answer:

organization

Explanation:

The answer is organization I am thinking.

Answer:

Used for everything from accessing the internet or printing a document to downloading an attachment from an email, networks are the backbone of business today. They can refer to a small handful of devices within a single room to millions of devices spread across the entire globe, and can be defined based on purpose and/or size.

We put together this handy reference guide to explain the types of networks in use today, and what they’re used for.

11 Types of Networks in Use Today

1. Personal Area Network (PAN)

The smallest and most basic type of network, a PAN is made up of a wireless modem, a computer or two, phones, printers, tablets, etc., and revolves around one person in one building. These types of networks are typically found in small offices or residences, and are managed by one person or organization from a single device.

2. Local Area Network (LAN)

We’re confident that you’ve heard of these types of networks before – LANs are the most frequently discussed networks, one of the most common, one of the most original and one of the simplest types of networks. LANs connect groups of computers and low-voltage devices together across short distances (within a building or between a group of two or three buildings in close proximity to each other) to share information and resources. Enterprises typically manage and maintain LANs.

Using routers, LANs can connect to wide area networks (WANs, explained below) to rapidly and safely transfer data.

3. Wireless Local Area Network (WLAN)

Functioning like a LAN, WLANs make use of wireless network technology, such as Wi-Fi. Typically seen in the same types of applications as LANs, these types of networks don’t require that devices rely on physical cables to connect to the network.

4. Campus Area Network (CAN)

Larger than LANs, but smaller than metropolitan area networks (MANs, explained below), these types of networks are typically seen in universities, large K-12 school districts or small businesses. They can be spread across several buildings that are fairly close to each other so users can share resources.

5. Metropolitan Area Network (MAN)

These types of networks are larger than LANs but smaller than WANs – and incorporate elements from both types of networks. MANs span an entire geographic area (typically a town or city, but sometimes a campus). Ownership and maintenance is handled by either a single person or company (a local council, a large company, etc.).

6. Wide Area Network (WAN)

Slightly more complex than a LAN, a WAN connects computers together across longer physical distances. This allows computers and low-voltage devices to be remotely connected to each other over one large network to communicate even when they’re miles apart.

The Internet is the most basic example of a WAN, connecting all computers together around the world. Because of a WAN’s vast reach, it is typically owned and maintained by multiple administrators or the public.

7. Storage-Area Network (SAN)

As a dedicated high-speed network that connects shared pools of storage devices to several servers, these types of networks don’t rely on a LAN or WAN. Instead, they move storage resources away from the network and place them into their own high-performance network. SANs can be accessed in the same fashion as a drive attached to a server. Types of storage-area networks include converged, virtual and unified SANs.

8. System-Area Network (also known as SAN)

This term is fairly new within the past two decades. It is used to explain a relatively local network that is designed to provide high-speed connection in server-to-server applications (cluster environments), storage area networks (called “SANs” as well) and processor-to-processor applications. The computers connected on a SAN operate as a single system at very high speeds.

9. Passive Optical Local Area Network (POLAN)

As an alternative to traditional switch-based Ethernet LANs, POLAN technology can be integrated into structured cabling to overcome concerns about supporting traditional Ethernet protocols and network applications such as PoE (Power over Ethernet). A point-to-multipoint LAN architecture, POLAN uses optical splitters to split an optical signal from one strand of singlemode optical fiber into multiple signals to serve users and devices.

10. Enterprise Private Network (EPN)

These types of networks are built and owned by businesses that want to securely connect its various locations to share computer resources.

11. Virtual Private Network (VPN)

By extending a private network across the Internet, a VPN lets its users send and receive data as if their devices were connected to the private network – even if they’re not. Through a virtual point-to-point connection, users can access a private network remotely.

Answer:

10 documents ^_^

Explanation:

I can open it at the same time on my laptop ●~●

Answer:

a. Youthful

Explanation:

The river gets its water from youth stage fluvial water. The river meanders from side to side. East Brownsville will be less stable in international boundary in terms of physical position on the landscape because its base level drops.

Explanation:

10:A program that assigns the sum 20,30,40

20: input 20,30,40

30:sum input

40: print total

End

Answer and Explanation:

Using Javascript programming language, to write this script we define a function that checks for empty variables with if...else statements and then uses a for loop to loop through all arguments passed to the function's parameters and print them out to the console.

function Check_Arguments(a,b,c){

var ourArguments= [];

if(a){

ourArguments.push(a);}

else( console.log("no argument for a"); )

if(b){

ourArguments.push(b);}

else( console.log("no argument for b"); )

if(c){

ourArguments.push(c);}

else( console.log("no argument for c"); )

for(var i=0; i<ourArguments.length; i++){

Console.log(ourArguments[i]);

}

}

Answer:

if (numCycles < 1){

        System.out.println("Too few.");

     }

     else if (numCycles > 4){

        System.out.println("Too many.");

        }    

  else{

     for(int i = 1; i <= numCycles; i++)

  {

     System.out.println(i + ": Lather and rinse.");

  }

     System.out.println("Done.");

  }

Explanation:

Answer: D. in addition to threats caused by malicious users, data can be lost by accident; for example: rats gnawing backup tapes

Explanation:

Data security is essential to protecting unwanted people from having access to ones data, malicious attack should also be prevented and unusual behavior should be monitored.

Data security has many facets such as threat nature, the nature of intruders, and cryptography. Furthermore, data integrity means that unauthorized users should not be able to modify any data without the owner's permission. Also, the statement that a common category of intruders are driven by determined attempts to make money; for example: bank programmers attempting to steal from the bank they work for is correct.

It should be no noted that rats gnawing backup tapes cannot prevent data loss. Therefore, the correct option is D