what is the account balance of an investment of 7,500after 25 years in an account earning 8% interest compounded continuously

Answer:

umm it's a piecewise function and I think the graph is correct I don't really understand what you mean by what is the "graph" of the following function since the graph is already there...

Step-by-step explanation:

Answer:

what can i help u with

Step-by-step explanation:

The graph of x = |y| is as shown in the figure.

When we draw a vertical line, it intersects the graph at two points.

This means for the same value of x , we have two values of y.

Or in other words, for the same pre image, we have two images.

Hence it is not a function.

But for every value of x, we do have a value of y, hence it is a relation.

x = |y| is a relation but it is not a function

Answer:

:B

Step-by-step explanation:

hope that can help

Answer:

(-1,3)

Step-by-step explanation:

Using midpoint formula, we have

x=(-4+2)/2=-1

y=(-2+8)/2=3

Answer:

x=7

Step-by-step explanation:

3/2x + 7/2 = 2x

Subtract 3/2x from each side

3/2x -3/2x + 7/2 = 2x-3/2x

7/2 = 2x -3/2x

Get a common denominator

7/2 = 4/2x - 3/2x

7/2 = 1/2 x

Multiply each side by 2

7/2 *2 = 1/2x*2

7 =x

Answer:

x=7

Step-by-step explanation:

im smart

Answer:

∠ L ≈ 21.6°

Step-by-step explanation:

Using the Sine rule in the triangle

[tex]\frac{MN}{sinL}[/tex] = [tex]\frac{LM}{sinN}[/tex] , that is

[tex]\frac{34}{sinL}[/tex] = [tex]\frac{42}{sin27}[/tex] ( cross- multiply )

42 × sinL = 34 × sin27° ( divide both sides by 42 )

sinL = [tex]\frac{34sin27}{42}[/tex] , then

∠ L = [tex]sin^{-1}[/tex] ( [tex]\frac{34sin27}{42}[/tex] ) ≈ 21.6° ( to the nearest tenth )

Answer:

cos Z = 8/17

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

cos theta = opp / hyp

cos Z = 16/34

cos Z = 8/17

Answer:

Answer is b

Step-by-step explanation:

cuh cuh cuh cuh cuh cuh , , , , , ,,

Answer:

x=7.5

Step-by-step explanation:

s is for students

d is for days

150 s take 5 days to finish food

if there are 100 s how many days will the same amount of food take

so 150 students × 5 days = 750 equation 1

100 students × x days= 100x equation 2

750 from 1 = 100 x from 2

750÷100=x

x=7.5 days

Answer:

Just agree on having ice cream

Step-by-step explanation:

Answer:

baba booey

Step-by-step explanation:

444

Answer:

X = 0.75 ( 1- n )

Step-by-step explanation:

let  X = the number one less than n gives (1-n)

75% of (1-n) = 0.75*(1-n) = 0.75(1-n)

In conclusion: X = 0.75 ( 1- n )

Answer:

48

Step-by-step explanation:

using the formula 1/2 b*h

8*12=96

96/2=48

Answer:

No. of children Frequency

0. 5

1. 7

2. 11

3. 5

4. 6

5 3

6 3

Step-by-step explanation:

Answer:

6.25

Step-by-step explanation:

[tex](-2\frac{1}{2})^2\\\\(-\frac{5}{2} )^2\\\\(\frac{5}{2})^2\\\\\frac{5^2}{2^2}\\\\\frac{25}{4}\\\\\boxed{6\frac{1}{4}}\text{ or } 6.25[/tex]

Hope this helps.

Answer:

older person: 32 yrs younger person: 5 yrs

Step-by-step explanation:

older person age: o

younger person age: y

o=5y+7

o+y=37

Solve with substitution:

5y+7+y=37

6y+7=37

6y=30

y=5

Plug back in:

o+5=37

o=32

Answer:

d) 16, 19, 14 + x

e) x + 20, 30, 33, 15, y - 20, x+x+20=60 and James would be 20.

f) 13

g) 120

Step-by-step explanation:

D.

(1) 14 + 2 = 16

(2) 14 + 5 = 19

(3) 14 + x

E.

(1) x + 20

(2) 10 + 20 = 30

(3) 13 + 20 = 33

(4) 35 - 20 = 15

(5) y - 20

(6) x + (x + 20) = 60 | 2x + 20 = 60 | 2x = 40 | x = 20

F.

200 - 148 = 52

52 / 4 = 13 each

G.

500 + 100 = 600

600 / 5 = 120 without the discount

Hope this helps!

Let a be first term

[tex]\\ \rm\longmapsto a_8=a+7d[/tex]

[tex]\\ \rm\longmapsto 26=a+7(3)[/tex]

[tex]\\ \rm\longmapsto a=26-21[/tex]

[tex]\\ \rm\longmapsto a=5[/tex]

Now

[tex]\\ \rm\longmapsto a_4=a+3d[/tex]

[tex]\\ \rm\longmapsto a_4=5+3(3)[/tex]

[tex]\\ \rm\longmapsto a_4=5+9[/tex]

[tex]\\ \rm\longmapsto a_4=14[/tex]

Answer:

y = ± 15

Step-by-step explanation:

Given

y² = 225 ( take the square root of both sides )

[tex]\sqrt{y^2}[/tex] = ± [tex]\sqrt{225}[/tex]

y = ± 15

That is y = 15, y = - 15

Since 15 × 15 = 225 and - 15 × - 15 = 225

y² = 225

y = √225

y = 15

y²= 225

y = √225

y = -15

y = ±15

Therefore values of y are 15 and -15

Must click thanks and mark brainliest

Step-by-step explanation:

First draw a lign segment like DF

Next keep the point on D make an arc by increasing the length of compass

As same keep the point on F make an arc lile same as before

Next there is apoint name it as any meeting on drew arc

connect it to the point with P

Answer:

Please find attached the drawing of ABCD, A'B'C'D', and A''B''C''D'', created with MS Excel

Step-by-step explanation:

The given composition of transformation is [tex]r_{y-axis} \ \circ \ r_{x = - 4}[/tex]

The transformation on the right, [tex]r_{x = - 4}[/tex], is carried out first as follows;

The point A with coordinate (-7, 7) reflected across the line x = -4, gives;

A(-7, 7) [tex]r_{x = - 4}[/tex] → A'(-1, 7)

Similarly, we have;

B(-5, 7) [tex]r_{x = - 4}[/tex] → B'(-3, 7)

C(-5, 1) [tex]r_{x = - 4}[/tex] → C'(-3, 1)

D(-7, 1) [tex]r_{x = - 4}[/tex] → D'(-1, 1)

Therefore, the image of the given rectangle after reflection across the lie, x = -4, is A'(-1, 7), B'(-3, 7), C'(-3, 1), and D'(-1, 1)

The second transformation, [tex]r_{y-axis}[/tex], is found as follows;

(x, y) [tex]r_{y-axis}[/tex] → (x, -y)

Therefore, we have;

A'(-1, 7) [tex]r_{y-axis}[/tex] → A''(-1, -7)

B'(-3, 7) [tex]r_{y-axis}[/tex] → B''(-3, -7)

C'(-3, 1) [tex]r_{y-axis}[/tex] → C''(-3, -1)

D'(-1, 1) [tex]r_{y-axis}[/tex] → D''(-1, -1)

The points ABCD, A'B'C'D', and A''B''C''D'' are plotted on MS Excel and the points joined with straight lines to form the drawing of the triangles as shown in the attached figure.

Answer:

Step-by-step explanation:

(a - b)(a + b) =a² - b²

(3x + 5)(3x -5) =(3x)² - 5² = 9x² - 25

(x +2)(x+2) = (x+ 2)² = x²+ 2*2*x+2² = x² + 4x + 4

(x+2)(3x -5 ) = x*3x - 5*x +2*3x +2*(-5)

                    = 3x² -5x +6x -10

                    = 3x² + x - 10

[tex]\frac{2*(3x+5)}{x+2}-\frac{5(x+2)}{3x-5}=3\\\\\frac{2*(3x+5)*(3x-5)}{(x+2)(3x-5)}-\frac{5*(x+2)(x+2)}{(3x-5)(x+2)}=3\\\\\frac{2*(9x^{2}-25)-5(x^{2}+4x+4)}{(3x-5)(x+2)}=3[/tex]

[tex]\frac{18x^{2}-25-5x^{2}-20x-20}{3x^{2}+x-10}=3\\\\\frac{18x^{2}-5x^{2}-20x - 25-20}{3x^{2}+x-10}=3\\\\[/tex]

13x² - 20x - 45 = 3*(3x² + x - 10)

13x² - 20x - 45 =9x² + 3x - 30

13x² - 9x² -20x - 3x - 45 + 30 = 0

4x² - 23x - 15 = 0

Answer:

Here is the detailed answer below

Step-by-step explanation:

Answer:

x = 5; y = 5

Step-by-step explanation:

One angle is a right angle, so its measure is 90 degrees.

One angle measures 45 degrees, so the unknown angle must also measure 45 degrees.

x and y are opposite two 45-degree angles, so x = y.

In a 45-45-90 triangle, the ratio of the lengths of the sides is

1 : 1 : sqrt(2)

We have

x : y : 5sqrt(2)

x/1 = 5sqrt(2)/sqrt(2)

x = 5

y = 5

Answer:

300 yd³

Step-by-step explanation:

Volume = lwh

l = 6

w = 5

h = 10

so, 6×5×10 = 300 yd³

Answer:

24

Step-by-step explanation:

Since the triangles are similar the side lengths must be proportional

2/12 = 4/PQ cross multiply expressions

2PQ = 48 divide both sides by 2

PQ = 24

Answer:

[tex]U = x[/tex]

[tex]V=10[/tex]

Step-by-step explanation:

Given

[tex](x +3)^2 + 14(x + 3) + 49 = (U + V)^2[/tex]

Required

Find U and V

We have:

[tex](x +3)^2 + 14(x + 3) + 49 = (U + V)^2[/tex]

Expand

[tex]x^2 + 6x + 9 + 14x + 42 + 49 = (U + V)^2[/tex]

Collect like terms

[tex]x^2 + 6x + 14x + 9 + 42 + 49 = (U + V)^2[/tex]

[tex]x^2 + 20x + 100 = (U + V)^2[/tex]

Expand

[tex]x^2 + 10x + 10x + 100 = (U + V)^2[/tex]

Group

[tex][x^2 + 10x] + [10x + 100] = (U + V)^2[/tex]

Factorize each group

[tex]x[x + 10] + 10[x + 10] = (U + V)^2[/tex]

Factor out x + 10

[tex][x + 10][x + 10] = (U + V)^2[/tex]

So, we have:

[tex][x + 10]^2 = (U + V)^2[/tex]

By comparison

[tex]U = x[/tex]

[tex]V=10[/tex]

Answer:

16

Step-by-step explanation:

[tex] \tan(x) = \frac{13}{46} [/tex]

[tex] \tan {}^{ - 1} ( \frac{13}{46} ) = 16[/tex]

Answer:

12

Step-by-step explanation:

[tex]\sqrt{64}[/tex] + [tex]\sqrt[3]{64}[/tex]

= 8 + 4

= 12

Square root of 64 = [tex] \sf \sqrt{64} = \sqrt{8 \times 8} = \boxed{\bf 8}[/tex]

Cube root of 64 = [tex] \sf \sqrt[3]{64} = \sqrt[3]{4 \times 4 \times 4} = \boxed{ \bf4}[/tex]

So,

Square root of 64 + Cube root of 64

[tex] = \sf \sqrt{64} + \sqrt[3]{64} \\ \sf = 8 + 4 \\ = \boxed{ \bf12}[/tex]

12 is the answer of the question asked.

____________

Hope it helps.

RainbowSalt2222