Answer:
0
Step-by-step explanation:
Degree is the Exponent of variable, and since root 11 do not contain any variable, we can write it as
[tex] \sqrt{11} {x}^{0} \\ = \sqrt{11} \times 1 \\ = \sqrt{11} [/tex]
Point of intersection Question:
Mike has $9.85 in dimes and quarters. If there are 58 coins altogether,
how many dimes and how many quarters does Mike have? Use the point of intersection to find the answer. Explain how you used a formula to calculate the # of quarters and dimes
Answers:
He has 27 quarters and 31 dimes
=========================================================
Work Shown:
d = number of dimes
q = number of quarters
d+q = 58 since there are 58 coins of only these two types
d = 58-q
10d+25q = 985 .... note that 985 cents is $9.85
10(58-q)+25q = 985 .... replace d with 58-q
580-10q+25q = 985
15q+580 = 985
15q = 985-580
15q = 405
q = 405/15
q = 27 ..... Mike has 27 quarters
d = 58-q
d = 58-27
d = 31 .... Mike also has 31 dimes
-----------
As a way to check:
d+q = 31+27 = 58 so that works out
and
10d+25q = 10*31+25*27 = 310+675 = 985
so that works out as well. The answer is confirmed.
12 less than a number is equal to the product of 7 and that number. Convert into an
equation and find the number?
Answer:
EQUATION: X - 12 = 7X. SOLUTION: X = - 2.
Step-by-step explanation:
First, we do not know the number. When the number is unknown, it is a variable. I chose the variable, "X."
12 less than signals that we subtract 12. So that would be X - 12.
A product of 7 AND that number means we multiply 7 by X. That can be notated as 7X.
12 less than X is EQUAL to the product of 7 and X. So X - 12 = 7X.
To find the solution, we want to know the value of X. Move X to one side of the equation.
X - 12 = 7X
-X -X
_________
-12 = 6X
Divide both sides by 6 to get X by itself.
X = - 2.
A
B
С
D
If mZACD = 70°, then mZBCD = [? ]°
Answer:
35 is correct
Step-by-step explanation:
hope this helps.
Answer:
35°
Step-by-step explanation:
Angle ACD is 70°. The little tick marks on the angle mean both sides of the split are the same amount. This means if you divide the angle in half, you will find out what both of them are equal to.
how to solve -4x+8y=-16
4x+3y=5
Answer:
X=2, y=-1
Step-by-step explanation:
-4x +8y=-16 equation 1
4x +3y=5 equation 2
11y=-11 add two equations to eliminate x
y=-1
solve for x by inputting y value into either equation
4x+3y=5
4x+3(-1)=5
4x-3=5
4x=8
x=2
A square is inscribed in an equilateral triangle that is inscribed in a circle.
A square is inscribed in an equilateral triangle that is inscribed in a circle. The square and circle are shaded.
Which represents the area of the shaded region?
area of the circle – area of the square – area of the triangle
area of the triangle – area of the square + area of the circle
area of the triangle + area of the square + area of the circle
area of the circle – area of the triangle + area of the square
The area of the shaded region is (area of the circle) - (area of the square) - (area of the triangle)
Option A is the correct answer
What is a triangle?A triangle is a 2-D figure with three sides and three angles.
The sum of the angles is 180 degrees.
We can have an obtuse triangle, an acute triangle, or a right triangle.
We have,
The shaded region consists of the area inside the circle but outside the square, as well as the area inside the equilateral triangle but outside the square.
Now,
The area of the circle is πr²
Since the square is inscribed in the circle, the diameter of the circle is equal to the diagonal of the square.
Let's say the side length of the square is s.
By the Pythagorean theorem,
s² + s² = (diameter)²
2s² = (2r)²
s² = r²
The area of the square is s² = r².
The area of an equilateral triangle with side length s is √(3)/4 x s².
Since the side length of the square is equal to the height of the equilateral triangle, the side length of the equilateral triangle is also equal to s.
The area of the shaded region.
= (area of the circle) - (area of the square) - (area of the triangle)
Thus,
The area of the shaded region is (area of the circle) - (area of the square) - (area of the triangle)
Learn more about triangles here:
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Find the sum.
b/ b^2+4b+4 + 9/b^2+7b+10
Answer:
11b^3+14b^2+b+9
---------------------------
b2
Step-by-step explanation:
decompose 17x^3+7x^2-17x-7 divided by (x-1)^2(x+1)^2 into partial fraction
..........................................................................................................................................................................................................................................................................................................................................................................................................................................................
Find the exact value of sin2Θ if tanΘ=[tex]\frac{-2\sqrt{5} }{5}[/tex] and 90 < Θ < 180.
Answer:
[tex]sin 2 \theta = \frac{4 \sqrt5}{9}[/tex]
Step-by-step explanation:
Identities used :
[tex]1. sin^2 \theta = 1 - cos^2\theta\\\\2. tan^2 \theta + 1 = sec^2 \theta\\\\3.cos \theta = \frac{1}{sec \theta} \\\\4. sin 2 \theta = 2 sin\theta cos\theta[/tex]
[tex]Given \ tan \theta = -\frac{2 \sqrt5}{5}\\[/tex]
[tex]we \ know \ tan ^2 \theta + 1 = sec^2\theta[/tex]
[tex](-\frac{2 \sqrt 5}{5})^2 + 1 = sec^2 \theta\\\\\frac{4 \times 5}{25 } + 1 = sec^2 \theta \\\\\frac{20 + 25}{ 25} = sec^2 \theta \\\\\frac{45}{25} = sec^2 \theta \\\\sec \theta = \sqrt{ \frac{45}{25}}\\\\sec \theta = \sqrt{ \frac{9 \times 5}{5 \times 5}} \\\\sec \theta = \frac{3 \sqrt {5}}{5}\\\\[/tex]
[tex]We \ know \ cos \theta = \frac{1}{ sec \theta}[/tex]
[tex]So , \cos \theta = \frac{5}{3 \sqrt5}[/tex]
[tex]Next \ sin^2 \theta = 1 - cos^2 \theta[/tex]
[tex]= 1 - (\frac{5}{3 \sqrt5})^2\\\\=1 - \frac{25}{9 \times 5}\\\\=1 - \frac{25}{45}\\\\=\frac{45 - 25}{45}\\\\=\frac{20}{45}\\\\=\frac{4}{9}[/tex]
[tex]sin \theta = \sqrt{ \frac{4}{9}} = \frac{2}{3}[/tex]
[tex]Find \ sin 2 \theta[/tex]
[tex]sin 2 \theta = 2 (sin \theta \times cos \theta)[/tex]
[tex]= 2 \times \frac{2}{3} \times \frac{5}{3\sqrt5}\\\\= \frac{4 \times \sqrt5 \times \sqrt5}{9 \times \sqrt 5}\\\\=\frac{4 \sqrt5}{9}[/tex]
What is the midpoint of the line segment with endpoints (-1,7) and (3, -3)?
A. (1, 2)
B. (1,4)
C. (2, 4)
D. (2, 2)
6. Tumigil si Jasmin ng 150 araw sa Taguig City dahil naabutan siya ng travel ban. Ilang buwan siya nanatili roon? *
Convert 23cm2 into mm2
Answer:
2300 mm^2
Step-by-step explanation:
What is the surface area of the right cylinder below?
18
A. 1194 sq. units
B. 880 sq. units
C. 3104 sq. units
D. 1759 sq. units
The surface area of the cylinder is 1759 sq units.
What is surface area?The surface area is the total area covered by all the faces of a 3D object. It is always measured in square units.
Given that a cylinder with radius 10 units and height is 18 units, we need to determine the surface area of the cylinder,
The surface area of the cylinder = 2π × radius × (height + radius)
= 2 × 3.14 × 10 × (18+10)
= 1759
Hence, the surface area of the cylinder is 1759 sq units.
Learn more about surface area, click;
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Which is a better estimate for the length of a raisin?
A. 1 meter b. 1 centimeter
Answer:
1 centimeter
Step-by-step explanation:
nope
Find x if 5, 9, 11, 12, 13, 14, 17 and x have a mean of 12.
Answer: 15
Step-by-step explanation: 5+9+11+12+13+14+17=81
Make an equation based on this and solve for the variable (x)
81+x/8=12
12*8=96
81+x=96
96-81=15
x=15
what number represents the same amount as 4 tens+0 ones
John invested $30000 in the bank for 4 years. At the end of the period, he had
$42520. Calculate
a. the interest earned
b. the rate per annum at which simple interest was earned to 1 decimal place.
Answer:
Rate = 10.4%
Step-by-step explanation:
Given :
P = $30000
A = $42520
Interest earned = 42520 - 30000 = $12520
Time = 4years
Find R
[tex]Interest = \frac{PRT}{100}[/tex]
[tex]12520 = \frac{30000 \times R \times 4}{100}\\\\12520 = 300 \times 4 \times R\\\\12520 = 1200 \times R\\\\R = \frac{12520}{1200}\\\\R = 10.43 \%[/tex]
Round to 1 decimal place, Rate = 10.4%
NEED HELP ASAP Let the function f(x) have the form f(x) = Acos(x+C). To produce a graph that matches the one shown below, what must the value of C be?
Answer:
[tex]C = 2[/tex] (A)
Step-by-step explanation:
We assume the constant A is different than 0
We notice that the graph of the function intercepts the x-axis when x = -0.5
we know that cos(x) = 0 when x = π/2 or x = -π/2
thus, [tex]-0.5 + C = \pi /2[/tex] or [tex]-0.5 + C = -\pi /2[/tex]
then [tex]C = \pi /2 + 0.5 = 2[/tex] or [tex]C = -\pi /2 = 0.5 = -1[/tex]
so [tex]C = 2[/tex]
A paper company needs to ship paper to a large printing business. The paper will be
shipped in small boxes and large boxes. Each small box of paper weighs 50 pounds
and each large box of paper weighs 80 pounds. A total of 19 boxes of paper were
shipped weighing 1280 pounds altogether. Determine the number of small boxes
shipped and the number of large boxes shipped.
Answer:
16 boxes large
Step-by-step explanation:
if the weigth is 1280 wilhich means its 1280÷80 =16
2. The average daily rainfall in London during April was 3.5 mm. How much rain fell during the month?
Answer:
105mm
Step-by-step explanation:
To find the rainfall during the month of April simply multiply the number of days in April times the average daily rainfall
Number of days in April: 30
Average daily rainfall: 3.5mm
Rainfall during the month = 30 * 3.5 = 105mm
Use the drop-down menus to correctly relate each pair of numbers
manee help meh son
Answer:
Sorry for the late response, I had to have lunch.
1. >
2. =
3. <
4. >
Step-by-step explanation:
Have a great summer :)
Find the distance between the points given.
(-3,-4) and (0,0)
Answer: 5 Units
Step-by-step explanation:
Find the IQR: (find the median, then find the median of the first group and then the next group. Now subtract big median minus the small median.) 20, 17, 16, 3, 7, 45
Answer:
13
Step-by-step explanation:
The IQR = Interquartile Range is the difference between the first and third quartile
Rearranged data set:
3, 7, 16, 17, 20, 45
Step 1
We find the first quartile = Q1
= 1/4(n + 1)th number
n = 6
= 1/4(6 + 1)th
= 1/4(7)th
= 1 3/4th number
This = 7
Step 2
We find the third quartile = Q3
= 3/4(n + 1)th number
n = 6
= 3/4(6 + 1)th
= 3/4(7)th
= 21/4th number
= 5 1/4 th number
This = 20
Step 3
IQR = Q3 - Q1
= 20 - 7
= 13
Can someone please help me out with this question
Answer:
C.
Step-by-step explanation:
In a right triangle, sin(40 - 2) = cos(32)'. What is the value of x?
O 10
O 15
O 20
O 25
Answer:
x = 25
Step-by-step explanation:
Correct question
In a right triangle Sin (40-x)=cos(3x) what is the value of x
Since Sin theta = Cos(90-theta)
Sin (40-x) = Sin(90-3x)
40 - x = 90 - 3x
-x+3x = 90 - 40
2x = 50
x = 25
Hence the value of x is 25
Need help with probabilities (math) plz
Answer:
What is your question for probabilities?
answer all the questions, just the answers, it's pythagorean theorem, plssss helpppp
Answer:
1. option c
2. option b
3. option b
Step-by-step explanation:
1 . option C
Square of longer side = sum of squares of other side
a)
5, 6 , 11
[tex]121 = 25 + 36\\does\ not \ satisfy[/tex]
b)
9, 12, 16
[tex]256 = 144 + 81\\Does\ not \ satisfy[/tex]
c)
7, 24, 25
[tex]625 = 576 + 49\\Does\ satisfy[/tex]
d)
12, 20, 25
[tex]625 = 400 + 144\\does \ not \ satisfy[/tex]
2. Option B
Square of longer side = sum of squares of other side
15 ² = 8 ² + r²
225 = 64 + r²
161 = r²
r = 12.688
r = 13ft
3 . Option b
To find length of AB, Use distance formula
[tex]AB = \sqrt{(x_2- x_1)^2 + (y_2 - y_1)^2}[/tex]
[tex]= \sqrt{(14-3)^2 + (6-1)^2}\\\\=\sqrt{11^2 + 5^2}\\\\=\sqrt{121 + 25}\\\\= \sqrt{146} \\= 12 \ ft[/tex]
hello i need help with these questions attached.
Answer:
Beep
Step-by-step explanation:
I need help
Solve the expression when X =5;3(X+2)=
[tex]\implies {\blue {\boxed {\boxed {\purple {\sf {21}}}}}}[/tex]
[tex]\large\mathfrak{{\pmb{\underline{\orange{Step-by-step\:explanation}}{\orange{:}}}}}[/tex]
[tex]3 \: ( \: x + 2 \: )[/tex]
Plugging in the value [tex]x = 5[/tex] in the above expression, we have
[tex] = 3\:( \: 5 + 2 \: )[/tex]
[tex] = 3 \: ( \: 7 \: )[/tex]
[tex] = 3 \times 7[/tex]
[tex] = 21[/tex]
Note:-[tex]\sf\pink{PEMDAS\: rule.}[/tex]
P = Parentheses
E = Exponents
M = Multiplication
D = Division
A = Addition
S = Subtraction
[tex]\red{\large\qquad \qquad \underline{ \pmb{{ \mathbb{ \maltese \: \: Mystique35☂}}}}}[/tex]
A rectangular garden has a length that is modeled by the expression2X -7 and a width of 3X^2+4x. What is the area of the garden?
Answer:
A = 6x³ - 13x² - 28xStep-by-step explanation:
Area of rectangle:
A = lwGiven:
l = 2x - 7w = 3x² + 4xThe area is:
A = (2x - 7)(3x² + 4x) =
2x(3x² + 4x) - 7(3x² + 4x) =
6x³ + 8x² - 21x² - 28x =
6x³ - 13x² - 28x
Answer:
Area of rectangle = 6 x ³ - 13 x ² + 28
step by step explanation
Given That :-
Length of rectangle = 2 x - 7Width of rectangle = 3 x ²+ 4 xTo Find :-
Area of rectangleFormula Used :-Area of rectangle = Length × Width
Solution : -Using Formula
Area of rectangle = Length × Width
substitute the values.
Area of rectangle = ( 2 x - 7 ) × ( 3 x ² + 4 )
= 2 x ( 3 x ² + 4 ) - 7 ( 3 x ² + 4 )
= 6 x ³ + 8 x - 21 x ² + 28
= 6 x ³ - 13 x ² + 28
whats the answer to this
Answer:
its the 2nd one
hope that helps<3
Answer:
jhkkkhj
Step-by-step explanation:
jkjkjkjkj
