v=u + 2at
Where v is the final velocity (in m/s), u is the initial velocity (in m/s), a is the
acceleration (in m/s?) and t is the time in seconds).
Find v when u is 35 m/s, a is 28 m/s2, and t is 58 seconds.
Answer:
3283m/s
Step-by-step explanation:
V=U+2at
V=35+2(28)(58)
V=35+3248
V=3283m/s
A farmer needs to cross the river with his fox, his chicken and a bag of corn. However, the boat can only fit the farmer and one other thing at a time. The problem is, the fox and the chicken are both hungry, so if he leaves the fox and chicken together, the fox might eat the chicken. If he leaves the chicken and corn together, the chicken might eat the corn. So how can the farmer get everyone across the river safely
first send the fox alone to the other side then send the corn, the fox wont eat the corn so that should be fine then lastly go with the farmer and the chicken, hope this helps!
PLEASE HELP WILL GIVE BRAINSLIST
Answer: 3. 55° 2. 225° 1. 125°
Step-by-step explanation: don't want brainliest
A polynomial p is graphed. What could be the equation of p? Choose 1 answer:
A. p(x) = x( x + 2)(2x + 7)
B. p(x) = x(x - 2)(2x - 7)
C. p(x) = x(2x) (7/2x)
D. p(x) = x(-2x)(- 7/2x)
Answer:
[tex]\text{B. }p(x)=x(x-2)(2x-7)[/tex]
Step-by-step explanation:
The zeroes of a function occur when the function crosses the x-axis. The function shown crossed the x-axis at [tex]x=0[/tex], [tex]x=2[/tex], and [tex]x=3.5[/tex]. These values of [tex]x[/tex] should produce an output of 0 when plugged into the function.
Therefore, the equation of the function graphed is [tex]\boxed{\text{B. }p(x)=x(x-2)(2x-7)}[/tex]
solve
[tex]100 {5}^{2} - 500 {5}^{6} [/tex]
Please help before 9:00 pm
Evaluate the following expression using the values given: (1 point)
Find 3x − y − 3z if x = −2, y = 1, and z = −2.
Algebra 1 proportional relationships
Answer:
It always pass through the origin.(0,0)
Which number belongs to the solution set of the equation?
x + 3 = 45
A. 15
B. 48
C. 43
D. 42
Answer:
D
Step-by-step explana
[tex] \sf \: The \: value \: of \: x \: is \: the \: number \: that \: belongs \: to \: the \: solution \: \\ \sf \: set \: of \: the \: equation. \: So \: we \: need \: to \: find \: x.[/tex]
[tex] \sf \: x + 3 = 45 \\ \sf \: x = 45 - 3 \\ \sf \: x = \underline{42}[/tex]
Answer ⟶ [tex]\boxed{\bf{D.42}}[/tex]
Explain how to solve 5^(x-2)= 8 using the change of base formula
Answer:
x = 3.3
Step-by-step explanation:
A equation is given to us and we need to solve out for x. The given equation is ,
[tex]\sf\longrightarrow 5^{x -2}= 8 [/tex]
Take log on both sides with base as " 10" . We have ,
[tex]\sf\longrightarrow log_{10} 5^{x-2}= log_{10}\ 8[/tex]
Simplify using the property of log , [tex]\sf log a^m = m log a [/tex] , we have ,
[tex]\sf\longrightarrow ( x -2) log_{10} 5 = log_{10} 8 [/tex]
Simplify ,
[tex]\sf\longrightarrow ( x -2 ) log_{10}5 = log_{10} 2^3[/tex]
Again simplify using the property of log ,
[tex]\sf\longrightarrow (x-2) log 5 = 3 log 2[/tex]
We know that log 5 = 0.69 and log 2 = 0.301 , on substituting this , we have ,
[tex]\sf\longrightarrow ( x - 2 ) = \dfrac{ 3\times 0.301}{0.69}[/tex]
Simplify the RHS ,
[tex]\sf\longrightarrow x - 2 = 1.30 [/tex]
Add 2 both sides ,
[tex]\sf\longrightarrow \boxed{\blue{\sf x = 3.30}}[/tex]
Hence the Value of x is 3.30 .
Answer:
its actually 3.292 because we round to the nearest thousandth and thats not even the equation you use above
Step-by-step explanation:
For this equation we use the formula log a^m=m (log a) so the equation will be written as log 5 (5^x-2) = log 5 (8). You use the base, which is 5, and use log to base 5 on both sides of the equation. Then you take the exponent " x-2" and write( x-2) log 5 (5) = log 5(8). Since log a =1, you multiply that 1 by x-2, which keeps it x-2. Making the equation x-2 = log 5 (8). Next, we use the change of the base properties with the formula log b^y= log y/ log b. The equation will be written as x-2 = log 8/ log 5, since 5 is the base it stays in the bottom or basement. We then add +2 to both sides of x-2 and log 8/ log 5. To solve this equation, you can find out what log 8 and log 5 are and divide those and add +2 to solve. So log 8 = 0.903 and log 5 = 0.698970 and divide those to get 1.29190 +2 and you get the answer rounded as 3.292.
Which shows a difference of squares?10 y squared minus 4 x squared16 y squared minus x squared8 x squared minus 40 x 2564 x squared minus 48 x 9
Answer:
16 y squared minus x squared
Step-by-step explanation:
The other all expressions except 16y²-x² doesn't complete the square and its difference. Then we can check 16y²-x²,
Now take the expression 16y²-x² and we can try to solve it.
We can simplify the terms separately to associate them as perfect squares,
→ 16y² = (4y)² --- (1)
→ x² = (1x)² --- (2)
Now we can take the difference of eq. (1) and eq. (2),
→ 16y²-x²
→ (4y)²-(1x)² --- (3)
Now eq. (3) shows a difference of squares.
Another representation is,
→ (4y - x) (4y + x)
→ 16y²- x²
→ (4y)²- (1x)²
Therefore, the expression 16y²-x² shows a correct difference of squares.
Answer:
its b trust
Step-by-step explanation:
state the dimensions of the matrix. identify the indicated element
Answer:
D; 2 * 3; -4
Step-by-step explanation:
The dimension of the matrix refers to the number of elements in a row multiplied by the number of elements is a column
In a row, we have 2 elements, in a column , we have 3 elements
So the matrix is of 2 * 3 dimension
a21, refers to the element in the matrix that is in the row 2 column 1 and that is -4
A block is being dragged along a horizontal surface by a constant horizontal force of size 45 N. It covers 8 m in the first 2 s and 8.5 m in the next 1 s. Find the mass of the block.
Answer: 15kg
Can anyone please explain this sum with proper working?
Answer:
Solution: To determine mass of the block we can use second Newton' law \vec F=m\vec a
F
=m
a
. The force and acceleration according the problem is directed along a horizontal surface, and we can omit the vector sign in Newton's law. The force we know F=45NF=45N, thus we should deduce the acceleration. The problem does not specify the initial speed at which time began to count, so for the first time interval, we may write the kinematics equation in the form
(1) S_1=v_1\cdot t_1+a\frac {t_1^2}{2}S
1
=v
1
⋅t
1
+a
2
t
1
2
, where S_1=8m, t_1=2s S
1
=8m,t
1
=2s , other quantities we don't know. The similar equation we can write for next time interval
(2) S_2=v_2\cdot t_2+ a\frac{t_2^2}{2}S
2
=v
2
⋅t
2
+a
2
t
2
2
. where S_2=8.5m, t_2=1s S
2
=8.5m,t
2
=1s
Note that during the first time interval, the speed of the block increased in accordance with the law of equidistant motion and it became the initial speed of the second interval, i.e.
(3) v_2=v_1+a\cdot t_1v
2
=v
1
+a⋅t
1
Substitute (3) to (2) we get
(4) S_2=(v_1+a\cdot t_1)\cdot t_2+ a\frac{t_2^2}{2}=v_1\cdot t_2+a\cdot t_1\cdot t_2+a\frac{t_2^2}{2}S
2
=(v
1
+a⋅t
1
)⋅t
2
+a
2
t
2
2
=v
1
⋅t
2
+a⋅t
1
⋅t
2
+a
2
t
2
2
From equation (1) and (4) we can exclude unknown quantity v_1v
1
, then remain only one unknown aa. For determine aa we dived (1) by t_1t
1
, (4) by t_2t
2
to find the average speed at time intervals and subtract (1) from (4).
(5) \frac {S_2}{t_2}-\frac {S_1}{t_1}=v_1+a\cdot t_1 +a\frac {t_2}{2}-(v_1+a\frac{t_1}{2})=a\frac{t_1+t_2}{2}-
t
2
S
2
−
t
1
S
1
=v
1
+a⋅t
1
+a
2
t
2
−(v
1
+a
2
t
1
)=a
2
t
1
+t
2
− For acceleration we get
(6) a=2\cdot ( {\frac{S_2}{t_2}-\frac{S_1}{t_1})/(t_1+t_2)}=2\cdot \frac{(8.5m/s-4m/s)}{3s}=3ms^{-2}a=2⋅(
t
2
S
2
−
t
1
S
1
)/(t
1
+t
2
)=2⋅
3s
(8.5m/s−4m/s)
=3ms
−2
For mass from second Newton's law we get
(7) m=\frac{F}{a}=\frac{45N}{3ms^{-2}}=15kgm=
a
F
=
3ms
−2
45N
=15kg
Answer: The mass of the block is 15 kg
what is the quotient
Answer:
The quotient is 4x+5 and the remainder is -13
Step-by-step explanation:
Using synthetic division
-5 4 25 12
Bringing down the 4 and multiplying
-5 4 25 12
↓ -20 -25
----------------------
4 5 -13
The quotient is 4x+5 and the remainder is -13
Answer:
4x +5 [tex]\frac{-13}{x+5}[/tex]
Step-by-step explanation:
. 4x +5 [tex]\frac{-13}{x+5}[/tex]
x + 5 | 4x^2 + 25x + 12
- 4x^2 + 20x
5x + 12
5x + 25
-13
The sum of two numbers is 90. The larger number is 14 more than 3 times the smaller number. Find the numbers.
[ x + y = 90 ; x = 14 + 3y ]
Answer:
fourteen times six equals eighty-four, eighty-four plus six equals 90
If 4 over 7 ton of concrete covers 7 over 8 of a bridge, how many tons of concrete are required to cover the entire bridge?
Answer:
Your answer would be 32/49.
Step-by-step explanation:
4/7 tons = 7/8 x
4/7 / 7/8
32/49
The tons of concrete are required to cover the entire bridge is 32/49 tons.
What are fractions?A fraction is a non-integer that is made up of a numerator and a denominator. An example of a fraction is 4/7.
How many tons is needed to cover the whole bridge?To determine this value, divide 4/7 by 7/8
4/7 ÷ 7/8
4/7 x 8/7 = 32/49 tons
To learn more about the division of fractions, please check: https://brainly.com/question/25779356
Urgent i need help!!…….
Answer:
Step-by-step explanation:
These are similar triangles. We know that because we know that all right triangles are similar. The height of the red one is 8 and the height of the blue one is 4; that means that the red one is twice the size of the blue one; likewise, the blue one is half the size of the red one. That means that ALL the measurements of these triangles exist in that ratio...even the base of the blue one. If the base of the red one is 3, and the red one is twice the size of the blue one, then the base of the blue one is 3/2 or 1.5. I can't see your choices because they are too small.
How many L of a 10% alcohol solution must be mixed with 9l of a 80% alcohol solution to make a 55% solution
Answer:
Step-by-step explanation:
The best thing to do for these solution/mixture problems is to make a table:
#L * %alcohol = L alcohol
10% sol.
+ 80% sol.
55% sol.
In this way, we can keep track of our information AND figure out the equation we need to use to solve it. Notice first, the equation along the top of the table:
#L * %alcohol = L alcohol This tells us that we are multiplying the #L column times the %alcohol column to get the L alcohol column. Notice second, that there is a + sign to the far left, indicating that we are ADDING rows 1 and 2 together to get the mix. Let's start filling this in. The easy part is the % alcohol column. 10% alcohol has .10 alcohol as a decimal, likewise for the 80% and 55%:
#L * %alcohol = L alcohol
10% sol. .10
+ 80% sol. .80 =
55% sol. .55
Now to fill in the first column. We know that our unknown, from the problem, is the number of Liters, #L in the 10% solution, so that is x, and we also know that we have 9 L of the 80% alcohol. Filling that in:
#L * %alcohol = L alcohol
10% sol. x * .10
+ 80% sol. 9 * .80
55% .55
Now look back at the + sign. We are told that we are mixing the 10% with the 80%, so we are adding them together. So let's do that. We will also follow the rule for the table and multiply the first column times the second column to fill in the last column to complete the table:
#L * %alcohol = L alcohol
10% sol. x * .10 = .10x
+ 80% sol. 9 * .80 = 7.2
55% sol. (9 + x) * .55 = .55x + 4.95
If we add the 2 solutions together to get the new solution in the first column, we will also add the L alcohol in the last column to get our equation:
.10x + 7.2 = .55x + 4.95 and
- .45x = - 2.25 so
x = 5L
We need 5 Liters of the 10% solution if we want to mix that with 9L of 80% solution to get 14 L of 55% solution.
Determine whether ABC are functions:
A. (2,5) (3,7) (-1,4) (0, 6)
B.(-3, 1) (4, 2) (5,-2) (-3,-1)
C. (3,4) (-4, 6) (-1,0) (0,1)
A.
B.
C.
Answer:
A. Function
B. Not a function
C. function
*Please Help!*
What is the volume of water, to the nearest tenth of a cubic metre, that would fill this spa tub?
First cylinder= 0.75m diameter, 0.80m height
Cylinder Underneath= 1.25m diameter, 0.70m height
Semi Sphere that holds both cylinders= 3m long
Answer:
The volume of water that will fill the spa tub is 5.9 cubic meters.
Step-by-step explanation:
Volume of water that would fill the spa tub = volume of semi sphere - (volume of the first cylinder + volume of the second cylinder)
i. volume of first cylinder = [tex]\pi[/tex][tex]r^{2}[/tex]h
where r is the radius and h is the height of the cylinder.
r = [tex]\frac{0.75}{2}[/tex] = [tex]\frac{3}{8}[/tex]
= 0.375 m
h = 0.80 m
volume of the first cylinder = [tex]\frac{22}{7}[/tex] x [tex](\frac{3}{8} )^{2}[/tex] x 0.8
= 0.3536 cubic meters
ii. volume of the cylinder underneath = [tex]\pi[/tex][tex]r^{2}[/tex]h
r = [tex]\frac{1.25}{2}[/tex] = [tex]\frac{5}{8}[/tex]
= 0.625
h = 0.70 m
volume of the cylinder underneath = [tex]\frac{22}{7}[/tex] x [tex](\frac{5}{8}) ^{2}[/tex] x 0.7
= 0.8594 cubic meters
iii. volume of the semi sphere = [tex]\frac{2}{3}[/tex] [tex]\pi[/tex][tex]r^{3}[/tex]
where r is the radius = 1.5 m
volume of the semi sphere = [tex]\frac{2}{3}[/tex] x [tex]\frac{22}{7}[/tex] x [tex](1.5)^{3}[/tex]
= 7.0714 cubic meters
Thus,
volume of the water to fill the spa tub = 7.0714 - (0.3536 + 0.8594)
= 5.8584
The volume of water that will fill the spa tub is 5.9 cubic meters.
what's is 11 divided by 620
Answer:
0.017741
Step-by-step explanation:
Plz someone do this for me I’ll give a lot of points
Answer:
RW is congruent to WX
Step-by-step explanation:
We know that PW and WV and Angle W is vertical angle so We need to include that RW congruent to WX.
Help this is due in 10 mins
Answer:
Only A is true
for sure
....................
Im not exactly understanding this question. Can someone please help me and possibly explain this to me?
Answer:
From the graph, when x=-6, y=1
so, your answer is A) f(x)=∛(x-6)+1
OAmalOHopeO
please me in the math
Find the H.C.F
[tex] {x}^{2} - 4 \\ {x}^{3} + 8 \\ {x}^{2} + 5x + 6[/tex]
it so simple
Step-by-step explanation:
Solution
First equation x ² - 4
= (x+2) (x-2)
Second equation = x ³ +8 + = x³+2^3
= (x-2) (x² + x₁2 +2²) = (x-2) (x² + 2x+4)
3 Third equation = x ² + 5x + 6
= x² + 6x= x +6 = x(x+6)-1(x+6)
(x-1) (x+6)
H.C. F= x-2
Grade improvement and study motivation
Answer:
yes because we are leraning new things
A restaurant freezes a cherry and lime juice mixture to create slushes. Cherry juice costs $5 per quart, and lime juice costs $3 per quart. Each day, the restaurant spends a total of $36 on 8 quarts of juice. The restaurant manager organizes the information in the table below.
Which equation can be used to determine the amount of cherry juice in each mixture?
5q + 3(8 – q) = 36
5q + 3(8 – q) = 8
q + (8 – q) = 8
q + 5 = 5q
Answer:
I think 5q+3(8-q) =36 is the answer for this question
Based on the amount the restaurant manager spends on the juice mixture, the amount of cherry juice can be found as 5q + 3(8 – q) = 8.
What is the amount of cherry juice used?Assuming the cherry juice is q and the lime juice is r, the following formulas would be true:
q + r = 8
5q + 3r = 36
The first equation can be rewritten as:
q + r = 8
r = 8 - q
Using substitution into the second formula we get:
5q + 3r = 36
5q + 3(8 - q) = 36
Find out more on simultaneous equations at https://brainly.com/question/16863577.
#SPJ9
PLS HELP 10 POINTS!!!
Identify the term whose coefficient is -12 in the expression:
98x – 12xy2 - 15xy2
Answer:
[tex] - 12xy {}^{2} [/tex]
Step-by-step explanation:
A coefficient is a rational number in front of multiple consecutive terms.
expand this question (x+5)(x-3)
find the cost of four score of plate at 50k each and three dozens of spoon at 20k each
Keith used the following steps to find the inverse of f, but he thinks he made a error
f(x) = 7x + 5
Answer:
Step-by-step explanation:
[tex]\Large \boldsymbol{} f(x) \ \ inverse \ \ function \ \ (f(x))^{-1} \\\\ y=7x+5 \\\\x=7y+5 \\\\ y=\dfrac{x-5}{7} \ \ or \ \ f(x)^{-1}= \dfrac{x-5}{7}[/tex]